Question

我一直在尝试从consumercomplaints中提取数据。标题和这些标题链接中的数据。我编写了以下代码，无法解析链接并提取数据，我也无法提取所有链接related.plz指南

from scrapy.contrib.spiders import CrawlSpider, Rule
from scrapy.selector import Selector
from scrapy.contrib.linkextractors.sgml import SgmlLinkExtractor
from urlparse import urljoin
from comp.items import CompItem

class criticspider(CrawlSpider):
    name ="comp"
    allowed_domains =["consumercomplaints.in"]
    #start_urls =["http://www.consumercomplaints.in/?search=delhivery&page=2","http://www.consumercomplaints.in/?search=delhivery&page=3","http://www.consumercomplaints.in/?search=delhivery&page=4","http://www.consumercomplaints.in/?search=delhivery&page=5","http://www.consumercomplaints.in/?search=delhivery&page=6","http://www.consumercomplaints.in/?search=delhivery&page=7","http://www.consumercomplaints.in/?search=delhivery&page=8","http://www.consumercomplaints.in/?search=delhivery&page=9","http://www.consumercomplaints.in/?search=delhivery&page=10","http://www.consumercomplaints.in/?search=delhivery&page=11"]
    start_urls=["http://www.consumercomplaints.in/?search=delhivery"]
    rules=(
        Rule(SgmlLinkExtractor(allow=("search=delhivery&page=1/+",)), callback="parse", follow=True),
        #Rule(SgmlLinkExtractor(allow=("startrow=\d",)),callback="parse_health",follow=True),
    )
    def parse(self,response):
        hxs = Selector(response)
        sites = hxs.select('//table[@width="100%"]')
        items = []

        for site in sites:
            item = CompItem()
            item['title'] = site.select('.//td[@class="complaint"]/a/span/text()').extract()
            item['link'] = site.select('.//td[@class="complaint"]/a/@href').extract()
            if item['link']:
                if 'http://' not in item['link']:
                    item['link'] = urljoin(response.url, item['link'])
                yield Request(item['link'],
                    meta={'item': item},
                    callback=self.anchor_page)

            # item['intro'] = site.select('.//td[@class="small"]//a[2]/text()').extract()
            # item['heading'] = site.select('.//td[@class="compl-text"]/div/b[1]/text()').extract()
            # item['date'] = site.select('.//td[@class="small"]/text()[2]').extract()
            # item['complaint'] = site.select('.//td[@class="compl-text"]/div/text()').extract()
            items.append(item)


    def anchor_page(self, response):
        hxs = Selector(response)
        old_item = response.request.meta['item'] # Receiving parse Method item that was in Request meta
        # parse some more values
        #place them in old_item
        #e.g
        old_item['data']=hxs.select('.//td[@class="compl-text"]/div/text()').extract()
        yield old_item

Answer 1

您使用的是旧版本的Scrapy吗？

在最新的稳定版本中，您不需要执行hxs = Selector(response)或使用hxs.select()方法。您可以使用response.xpath()执行相同的操作。

我认为代码中的问题是select()（或response.xpath）的结果实际上是Python list，所以你需要这样做：

link = site.select('.//td[@class="complaint"]/a/@href').extract()
if link:
    item['link'] = link[0]

你可能也希望为标题做类似的事情。

编辑：我做了一些改动：

import scrapy
from scrapy.contrib.spiders import CrawlSpider, Rule
from scrapy.selector import Selector
from scrapy.contrib.linkextractors.sgml import SgmlLinkExtractor
from urlparse import urljoin


class CompItem(scrapy.Item):
    title = scrapy.Field()
    link = scrapy.Field()
    data = scrapy.Field()


class criticspider(CrawlSpider):
    name = "comp"
    allowed_domains = ["consumercomplaints.in"]
    start_urls = ["http://www.consumercomplaints.in/?search=delhivery"]
    rules = (
        Rule(
            SgmlLinkExtractor(allow=("search=delhivery&page=1/+",)),
            callback="parse",
            follow=True),
    )

    def parse(self, response):
        sites = response.xpath('//table[@width="100%"]')
        items = []

        for site in sites:
            item = CompItem()
            item['title'] = site.xpath('.//td[@class="complaint"]/a/span/text()').extract()[0]
            item['link'] = site.xpath('.//td[@class="complaint"]/a/@href').extract()[0]
            if item['link']:
                if 'http://' not in item['link']:
                    item['link'] = urljoin(response.url, item['link'])
                yield scrapy.Request(item['link'],
                                     meta={'item': item},
                                     callback=self.anchor_page)

            items.append(item)

    def anchor_page(self, response):
        old_item = response.request.meta['item']

        old_item['data'] = response.xpath('.//td[@class="compl-text"]/div/text()').extract()
        yield old_item

使用scrapy提取链接内的数据

1 个答案: