所以我做了这个,但是当我输入一个字符串时,它只能检测到一个字符 并且它也不会将输入的字符串转换为小写
Dim readme, readme2 As String
Dim j, i As Integer
Dim Compare As Integer
readme = TextBox1.Text
readme2 = TextBox2.Text
readme.ToLower.Substring(i, readme.Length)
readme2.ToLower.Substring(j, readme2.Length)
For i = 0 To readme.Length
For j = 0 To readme2.Length
If readme = readme2 Then
Compare = +1
End If
Next
Next
Label4.Text = Compare`enter code here`
答案 0 :(得分:1)
字符串是不可变的。您不能将方法应用于字符串,并期望该字符串更改以响应该方法的内部操作 您需要将操作的结果重新分配给您用于调用方法的相同字符串
readme = readme.ToLower()
readme2 = readme2.ToLower()
你问题的第二部分更加困惑,你是否试图计算同一位置的平等字符数?
在这种情况下,你的循环应该是
Dim maxLenToCheck = Math.Min(readme.Length, readme2.Length)
For i = 0 To maxLenToCheck - 1
If readme(i) = readme2(i) Then
Compare += 1
End If
Next
在该循环中,您始终将Compare设置为1,正确的语法是递增Compare变量
Compare += 1
按照下面的评论,我假设您的循环应该写为
Dim Compare = 0
For i = 0 To readme.Length - 1
for j = 0 to readme2.Length -1
If readme(i) = readme2(j) AndAlso _
Not Char.IsWhiteSpace(readme(i)) Then
Compare += 1
End If
Next
Next
答案 1 :(得分:0)
根据Steve在解决方案中的评论,作者希望知道两个字符串中出现的字母数,忽略大小写和空格。
然而,根据我的计算,解决方案应该是21,而不是20.这是一个使用LINQ的解决方案,它也提供了这些字母所在位置的可视反馈:
Public Class Form1
Private Class LetterCount
Public Letter As Char
Public Count As Integer
Public Overrides Function ToString() As String
Return Letter & " : " & Count
End Function
End Class
Private Sub Form1_Load(sender As Object, e As EventArgs) Handles MyBase.Load
TextBox1.Text = "This is a Test"
TextBox2.Text = "This should be tryed before"
RichTextBox1.ReadOnly = True
RichTextBox1.Font = New Font("MS Courier", 14) ' monospaced font
End Sub
Private Sub Button1_Click(sender As Object, e As EventArgs) Handles Button1.Click
RichTextBox1.Text = TextBox1.Text & vbCrLf & TextBox2.Text & vbCrLf
Dim charsA As New List(Of Char)(TextBox1.Text.ToLower.ToCharArray.Where(Function(x) Not Char.IsWhiteSpace(x)))
Dim charsB As New List(Of Char)(TextBox2.Text.ToLower.ToCharArray.Where(Function(x) Not Char.IsWhiteSpace(x)))
Dim DistinctCommonLetters = (From A In charsA, B In charsB Where A = B Select A).Distinct
Dim DistinctCounts =
From Letter In DistinctCommonLetters, C In charsA.Concat(charsB)
Where C = Letter
Group By Letter Into Group
Select New LetterCount With {.Letter = Letter, .Count = Group.Count}
Dim TotalMatches = DistinctCounts.Sum(Function(x) x.Count)
ListBox1.DataSource = DistinctCounts.ToList
Label1.Text = "TotalMatches: " & TotalMatches
End Sub
Private Sub ListBox1_SelectedIndexChanged(sender As Object, e As EventArgs) Handles ListBox1.SelectedIndexChanged
Dim LC As LetterCount = ListBox1.SelectedItem
RichTextBox1.SelectAll()
RichTextBox1.SelectionColor = Color.Black
Dim index As Integer = RichTextBox1.Find(LC.Letter, 0, RichTextBoxFinds.None)
While index <> -1
RichTextBox1.Select(index, 1)
RichTextBox1.SelectionColor = Color.Red
index = RichTextBox1.Find(LC.Letter, index + 1, RichTextBoxFinds.None)
End While
End Sub
End Class