如何将多个sed输出行（-e）连接到一行

Question

我使用sed从日志文件中提取一些数据。我的命令如下：

sed -n -e 's/.*\(date\).*/\1/p' -e 's/.*\(details in that entry\).*/\1/p'-e 's/.*\(some more details\).*/\1/p'

这总是产生2行或更多行：

date
some details
some more details
date(2nd entry) 
some details ( 2nd entry ) 
some more details (2nd entry) 

依旧......

如何将来自sed命令集的行直接加入到这样的一行？

date some details some more details
date some details some more details....

Answer 1

它的第3行：

awk 'ORS=NR%3?" ":RS' file
date some details some more details
date some details some more details

或

paste -d " " - - - < file
date some details some more details
date some details some more details

---

如果您可以使用date作为触发词，则可以使用此gnu awk

awk 'NR>1 {$1=RS FS $1;print}' RS="date" file
date some details some more details
date some details some more details

（由gnu awk中的多个字符组成的RS）