Question

关于我的django查询，我有一个主要问题。我的疑问是： -

query=AllTime.objects.values('startdate').order_by('timeid').annotate(spent=Sum('spent')).filter(project_id=project_id,startdate__range=(datetime.datetime.now()-datetime.timedelta(days=15),datetime.datetime.now()))

查询给出了以下输出： -

{
    "startdate": "2015-01-12",
    "spent": 84
},
{
    "startdate": "2015-01-13",
    "spent": 7
},
{

    "startdate": "2015-01-19",
    "spent": 32
}

问题是我得到的是那些已经在我桌子上的日期。但我想要像这样的输出

{
    "startdate": "2015-01-12",
    "spent": 84
},
{
    "startdate": "2015-01-13",
    "spent": 7
},
{
    "startdate": "2015-01-14",
    "spent": 0
},
{
    "startdate": "2015-01-15",
    "spent": 0
},
{
    "startdate": "2015-01-16",
    "spent": 0
},
{
    "startdate": "2015-01-17",
    "spent": 0
},
{
    "startdate": "2015-01-18",
    "spent": 0
},
{

    "startdate": "2015-01-19",
    "spent": 32
}

如何获取django query ???的上述输出

Answer 1

您无法创建此类查询。唯一的方法是创建一个包含所有必需日期值的列表：

days_to_show = 15
start_date = datetime.date.today() - datetime.timedelta(days=days_to_show)

query = AllTime.objects.values('startdate').order_by('timeid') \
               .annotate(spent=Sum('spent')) \
               .filter(project_id=project_id,
                       startdate__range=(start_date, datetime.datetime.now()))

spent_dict = dict((d['startdate'], d['spent']) for d in query)

date_list = [(start_date + datetime.timedelta(days=day)).strftime('%Y-%m-%d')
                                 for day in range(0, days_to_show)]
spent_list = [{'startdate': date, "spent": spent_dict.get(date, 0)}
                                 for date in date_list]

django查询日期时间

1 个答案: