Question

我必须获得标签的计数编号

<name></name>

列。

<users><name>Tomek</name><name>Pawel</name><name>Krzysiek</name></users>

在此示例数据中，查询应返回3.

Answer 1

使用XPath可以轻松实现逻辑。

您的方案的示例XPath：count（/ users / name）

结果：3

Test Here

Answer 2

动态sql解决方案：

DECLARE @Table TABLE (Names NVARCHAR(1100))
INSERT INTO @Table VALUES
    ('<users><name>Tomek</name><name>Pawel</name><name>Krzysiek</name></users>'),
    ('<users><name>Tomek</name><name>Pawel</name><name>Krzysiek</name></users>'),
    ('<users><name>Tomek</name><name>Pawel</name><name>Krzysiek</name></users>')

DECLARE @Sql NVARCHAR(MAX)
SET @Sql = ''

SELECT
    @Sql = @Sql +

    REPLACE(
        REPLACE(
            REPLACE(
                REPLACE(Names,'</name>',''' as Names UNION ALL ')
            ,'<name>','SELECT ''')
        ,'</users>','')
    ,'<users>','')+CHAR(10)
FROM @Table

SET @Sql = LEFT(@Sql,LEN(@Sql)-11) 
SET @Sql = 'SELECT COUNT(Names) AS Names FROM (' + @Sql + ') as AllNames'
EXEC(@Sql)

Answer 3

如果您使用xml数据，请尝试此变体

DECLARE @XMLdata XML = N'<users><name>Tomek</name><name>Pawel</name><name>Krzysiek</name></users>'
SELECT  COUNT(*) 
FROM @XMLdata.nodes('/users/name') col ( name )

当数据存储为字符串（varchar）

时，此变体可能很有用

--create temp table for testing
IF OBJECT_ID('Tempdb..#Tags') IS NOT NULL 
    DROP TABLE #Tags
CREATE TABLE #Tags
    (
      SampleText VARCHAR(1000)
    )
INSERT  INTO #Tags
        ( SampleText )
VALUES  ( '<users><name>Tomek</name><name>Pawel</name><name>Krzysiek</name></users>' ),
        ( '<users><name>Somik</name><name>Pawel</name><name>Krzysiek</name></users>' ),
        ( '<users><name>Krolik</name><name>Pawel</name><name>Krzysiek</name></users>' ),
        ( '<users><name>Domik</name><name>Pawel</name><name>Krzysiek</name></users>' ),
        ( '<users><name>Zontik</name><name>Pawel</name><name>Krzysiek</name></users>' );
--------------------------------------------------------------------------------
--  recursive cte for split string
WITH    cte
          AS ( SELECT   n = 1
               UNION ALL
               SELECT   n + 1
               FROM     cte
               WHERE    n <= 1000
             )
--------------------------------------------------------------------------------
-- final query
        SELECT  COUNT(*) AS Cnt
        FROM    cte
                JOIN #Tags AS T ON n <= LEN(T.SampleText)
        WHERE   SUBSTRING(T.SampleText, n, 7) = '</name>'
OPTION  ( MAXRECURSION 1000 )

计算列中的单词

3 个答案: