Question

我的任务中有几个目标，我要读一个文件，我相信我做的正确，并从整数文件中，把它放到一个数组中。它不会让我编译代码，它会在最小的时候出现错误。那么，我该如何打印出min的方法？

public class jlrogers2 {

public static void reader(int[] arr) throws FileNotFoundException { 

 Scanner scanner = new Scanner(new FileReader("numbers.txt"));
    int i = 0;

    while(scanner.hasNextInt())
    {
        arr[i++] = scanner.nextInt();
    }


}

public static int minnimum(int[] arr){

int smallest =arr[0];

for (int i = 1; i>arr.length; i++){
        if (arr[i] > smallest)
        {
            smallest= arr[i];
            System.out.println(smallest);
        }
    }
    return smallest;
}
 public static void main(String [] args) throws FileNotFoundException   
{  


    Scanner in = new Scanner (System.in);
    System.out.println("Enter 1 for max index value.\nEnter 2 for min index   value.\nEnter 3 to search for an index value.\n"
            + "Enter 4 for display all index's\nEnter 5 for numbers in a range.\nEnter 6 to exit menu. ");

    int number = in.nextInt();

    if(number==6){
        System.out.println("Thank you for being awesome");
    }

    if (number==5){
    System.out.println(minnimum(smallest))  // here is my issue }


}

}

Answer 1

将for (int i = 1; i>arr.length; i++)更改为for (int i = 0; i<arr.length; i++) 你找到最小的逻辑也是错误的。实际上你找到了最大的。

找到最小的把它当作

在if(arr[i] < smallest )循环

中

for

将主要内容更改为

 public static void main(String [] args) throws FileNotFoundException   
{  

 Scanner in = new Scanner (System.in);
 System.out.println("Enter 1 for max index value.\nEnter 2 for min index   value.\nEnter 3 to search for an index value.\n"
        + "Enter 4 for display all index's\nEnter 5 for numbers in a range.\nEnter 6 to exit menu. ");

 int number = in.nextInt();
 int arr[] = new int [200];//change this according to the requirement
 if(number==6){
    System.out.println("Thank you for being awesome");
}

if (number==5){
  reader(arr); 
 System.out.println(minnimum(arr)); 
 }
}

Answer 2

您的代码似乎存在许多问题： -

- ＆gt;首先，其他人已将更改for (int i = 1; i>arr.length; i++)指向for (int i = 1; i<arr.length; i++)

- ＆GT;使用的变量int smallest不是类级变量，也不会在main()

中进行本地声明

- ＆GT;方法minimum()永远不会从main调用，方法reader()似乎也不会被调用

- ＆GT;使用后关闭扫描仪，在方法结束时调用scanner.close()

进行一些更改： -

- ＆GT; main()现在看起来像： -

public static void main(String [] args) throws FileNotFoundException   
{  
    int[] arr=new int[100];
    reader(arr);//call this to populate arr[]
    Scanner in = new Scanner (System.in);
    System.out.println("Enter 1 for max index value.\nEnter 2 for min index   value.\nEnter 3 to search for an index value.\n"
            + "Enter 4 for display all index's\nEnter 5 for numbers in a range.\nEnter 6 to exit menu. ");

    int number = in.nextInt();

    if(number==6){
        System.out.println("Thank you for being awesome");
    }

    if (number==5){
        System.out.println(minnimum(arr));
    }

   in.close();
}

Answer 3

要找到需要更改循环的最小元素，请执行以下操作：

for (int i = 1; i < arr.length; i++) 
{
      if (arr[i] < smallest)
      {
        smallest = arr[i];
      }
}

在System.out中使用方法不起作用？

3 个答案: