Question

我已成功设置了如何使用以下代码完成二进制加法，

#include <stdio.h>
#include <iostream>
using namespace std;

int main() {    

    long a, b;
    int i = 0, r = 0, sum[20];

    cout << "Enter the first binary number: ";

    cin >> a;

    cout << "Enter the second binary number: ";

    cin >> b;

    while (a != 0 || b != 0)
    {
        sum[i++] = (a % 10 + b % 10 + r) % 2;
        r = (a % 10 + b % 10 + r) / 2;
        a = a / 10;
        b = b / 10;
    }
    if (r != 0)
        sum[i++] = r;
    --i;
    cout << "The sum of the two binary numbers is: ";
    while (i >= 0)
        cout << sum[i--];
    cout << ". ";

    system("pause");
    return 0;
}

我需要使用类似的方法来允许二进制减法和乘法。我尝试了以下代码，但它没有按计划运行。添加if语句（如果c = 1）会导致循环继续多次，从不给出正确的答案。单独使用减法公式，给出与添加相同的结果。有人可以帮我解决这个问题吗？感谢

#include <stdio.h>
#include <iostream>
using namespace std;

int main() {

    long a, b;

    int c = 0;

    cout << "Enter the first binary number: ";

    cin >> a;

    cout << "Enter the second binary number: ";

    cin >> b;

    cout << "Which operation do you want to complete: Add=1, Subtract=2, Multiply=3: ";

    cin >> c;

    if (c = 1){
        while (a != 0 || b != 0)
        {
            int i = 0, r = 0, sum[20];
            sum[i++] = (a % 10 + b % 10 + r) % 2;
            r = (a % 10 + b % 10 + r) / 2;
            a = a / 10;
            b = b / 10;
        }
        if (r != 0)
            sum[i++] = r;
        --i;
        cout << "The sum of the two binary numbers is: ";
        while (i >= 0)
            cout << sum[i--];
        cout << ". ";
    }

    if (c = 2) {
        while (a != 0 || b != 0)
        {
            int i = 0, r = 0, sub[20];
            sub[i++] = (a % 10 - b % 10 + r) % 2;
            r = (a % 10 - b % 10 + r) / 2;
            a = a / 10;
            b = b / 10;
            if (r != 0)
                sub[i++] = r;
            --i;
            cout << "The difference of the two binary numbers is: ";
            while (i >= 0)
                cout << sub[i--];
            cout << ". ";
        }
    if (c = 3) {
        while (a != 0 || b != 0)
        {
            int i = 0, r = 0, prod[20];
            prod[i++] = (a % 10 * b % 10 + r) % 2;
            r = (a % 10 * b % 10 + r) / 2;
            a = a / 10;
            b = b / 10;
            if (r != 0)
                prod[i++] = r;
            --i;
            cout << "The product of the two binary numbers is: ";
            while (i >= 0)
                cout << prod[i--];
            cout << ". ";
        }
    }
}

Answer 1

此指定 1到c

if (c = 1){

将 c与1进行比较。

if (c == 1){

请打开编译器的警告。你会被告知像这样的拼写错误。

需要使用初学者逻辑创建C ++二进制计算器

1 个答案: