我有一个projects
表(列id
和name
),一个categories
表(列id
和name
)和一个加入表projects_categories
(列project_id
和category_id
)。
我想编写一个返回属于一组类别的所有项目的查询。例如,如果我有
projects id name 1 foo 2 bar
categories id name 1 bee 2 gee
projects_categories project_id category_id 1 1 1 2 2 1
我想编写一个返回项目的查询" foo"如果我传递类别ID 1和2.我尝试了以下查询,但它返回属于类别1或2的所有项目,而不是类别1和2。
SELECT "projects".*
FROM "projects"
INNER JOIN "projects_categories" ON "projects_categories"."project_id" = "project"."id"
WHERE "projects_categories"."category_id" IN (1, 2)
以下查询不会返回任何结果:
SELECT "projects".*
FROM "projects"
INNER JOIN "projects_categories" ON "projects_categories"."project_id" = "project"."id"
WHERE "projects_categories"."category_id" = 1
AND "projects_categories"."category_id" = 2
我理解为什么这些查询会返回这些结果,但无法弄清楚如何编写我需要的查询。
答案 0 :(得分:2)
您可以尝试EXISTS
:
SELECT "p".*
FROM "projects" "p"
WHERE EXISTS (
SELECT *
FROM "projects_categories" "pc"
WHERE "pc"."category_id" IN (1, 2)
AND "pc"."project_id" = "p"."id"
GROUP BY "pc"."project_id"
HAVING COUNT(DISTINCT "pc"."project_id" ) = 2)
)
或JOIN
:
SELECT "p".*
FROM "projects" "p"
JOIN (
SELECT "pc"."project_id"
FROM "projects_categories" "pc"
WHERE "pc"."category_id" IN (1, 2)
GROUP BY "pc"."project_id"
HAVING COUNT(DISTINCT "pc"."project_id" ) = 2)
) "tpc" ON "tpc"."project_id" = "p"."id"
或IN
:
SELECT "p".*
FROM "projects" "p"
WHERE "p"."id" IN (
SELECT "pc"."project_id"
FROM "projects_categories" "pc"
WHERE "pc"."category_id" IN (1, 2)
GROUP BY "pc"."project_id"
HAVING COUNT(DISTINCT "pc"."project_id" ) = 2)
)
答案 1 :(得分:0)
问题是查询正在查看同一个表和列,并尝试使用两个不同的值。这将分离两个不同的条件,然后将它们组合成一个结果集。
SELECT A.ProjectName, A.CategoryId, B.CategoryId
FROM
(SELECT P.Name [ProjectName], PC.CategoryId, PC.ProjectId
FROM @Projects P
INNER JOIN @Project_Categories PC
ON PC.ProjectId = P.ID
WHERE PC.CategoryId = 1
) A
INNER JOIN (SELECT P.Name [ProjectName], PC.CategoryId, PC.ProjectId
FROM @Projects P
INNER JOIN @Project_Categories PC
ON PC.ProjectId = P.ID
WHERE PC.CategoryId = 2
) B
ON A.ProjectId = B.ProjectId