Question

我在php文件中写了查询，我的查询是：

$query = "SELECT cc.NAME complex_check_name,f.name server_name,
                sgk.NAME single_check_name,cc.operator 
          FROM complex_check cc, 
               lnksinglechecktocomplexcheck lk,
               single_checks sgk,
               functionalci f ,
               lnkconfigurationitemtosinglecheck lkcg 
           WHERE cc.id = lk.complex_check_id AND 
                 sgk.id = lk.single_check_id and 
                 sgk.id = lkcg.single_check_id AND 
                 lkcg.config_item_id = f.id ";

if ($result=mysqli_query($link,$query))
{
    while ($obj=mysqli_fetch_object($result))
    {
       $list= $obj->complex_check_name . 
              "@".
              $obj->server_name .
              ";". 
              $obj->single_check_name . 
              $obj-> operator;

        echo  $list .'<br>'; 
    }
 }

结果是：

test_com_check_sep01@INFRASEP01;cpu check sep01&
test_com_check_sep01@INFRASEP01;DB check sep01&
test_com_check_sep01@INFRASEP01;disk space check sep01&
test_com_check_sep02@INFRASEP02;cpu check sep02||
test_com_check_sep02@INFRASEP02;db check sep02||
test_com_check_sep02@INFRASEP02;disk space check sep02||

如何将字符串连接为：

"test_com_check_sep01=INFRASEP01;cpu check sep01&INFRASEP01;DBcheck sep01&INFRASEP01;disk space check sep01"

"test_com_check_sep02=INFRASEP02;cpu check sep02||INFRASEP02;db check sep02||INFRASEP02;disk space check sep02"

Answer 1

试试这个

$concat1 = '';
$concat2 = '';
if ($result=mysqli_query($link,$query))
  {
      while ($obj=mysqli_fetch_object($result))
        {
           if($obj->server_name == 'INFRASEP01'){
                concat1 .= $obj->complex_check_name . "@".$obj->server_name .";". $obj->single_check_name . $obj-> operator;
           }else{
                concat2 .= $obj->complex_check_name . "@".$obj->server_name .";". $obj->single_check_name . $obj-> operator;
           }
        }
   }
echo  $concat1 .'<br>'.$concat2;

Answer 2

假设你想要将这些线分开使用，你可以这样做

$list = array("INFRASEP01", "INFRASEP01", "INFRASEP02");
$concatINFRASEP01 = "";
$concatINFRASEP02 = "";
for($lineCounter = 0; $lineCounter < sizeof($list); $lineCounter++)
    if(strpos($list[$lineCounter], "INFRASEP01") !== false){
        //Found it
        $concatINFRASEP01 .= " " . $list[$lineCounter];
    }
    else if(strpos($list[$lineCounter], "INFRASEP02") !== false){
        $concatINFRASEP02 .= " " . $list[$lineCounter];
    }

注意：我没有测试此代码，因此可能存在错误。

如果你不需要$ list数组，那么你可以像@Malakiof建议那样做。

编辑（2015年1月22日）：我已经改进了我的答案，但是如果我误解的话就把旧答案留在那里。

//In your case the rows come from the $obj (which most would call $row)
$listOfRows = array("test_com_check_sep01@INFRASEP01;cpu check sep01&","test_com_check_sep01@INFRASEP01;DB check sep01&", "test_com_check_sep02@INFRASEP02;cpu check sep02||");

//Create this array as you go through each row by adding the server_name
//to this array. You can skip making this array and simply make the
//unique array by checking if the array contains the server_name.
$listServerNames = array("INFRASEP01","INFRASEP02","INFRASEP01", "INFRASEP02", "INFRASEP01");

//Only have unique server names to avoid duplicates
$listUniqueServerNames = array_unique($listServerNames);

//this will be your list of concatenated strings
$concatByServerName = array();

//Go through the unique server names one by one
foreach($listUniqueServerNames as $serverName)
//While looking at each unique server name, look through the rows
foreach($listOfRows as $line)
if(strpos($line, $serverName) !== false){
    //Found it
if(array_key_exists($serverName, $concatByServerName))
    $concatByServerName[$serverName] .= " " . $line;
else
    $concatByServerName[$serverName] = $line;
}

如果$ listOfRows非常大，请考虑制作$ listOfRows的副本，并在将它们添加到$ concatByServerName时从$ listOfRows中删除这些行。

虽然这不是最好的方法，但我努力保持简单，以便您能够让它工作，同时充分了解正在发生的事情。您可以通过查看项目并简化这些任务来轻松改进此代码。

Answer 3

您可以将值存储到数组中，然后内爆。

$check  =   array();
if($result = mysqli_query($link,$query)) {
        while($obj = mysqli_fetch_object($result)) {
            // If value is not stored in check array proceed
            if(!in_array($obj->complex_check_name,$check))
                $list[$obj->complex_check_name][]   =   $obj->complex_check_name."=";

            $list[$obj->complex_check_name][]   =   $obj->server_name.";".$obj->single_check_name.$obj->operator;

            // Store in check array
            $check[]    =   $obj->complex_check_name;
        }

    // Loop through stored rows and implode with break
    foreach($list as $array) {
            echo implode("<br />",$array);
        }
 }

如何在PHP条件下连接字符串？

3 个答案: