Question

with tempfile.NamedTemporaryFile(delete = False) as tmpfile:
    subprocess.call(editor + [tmpfile.name])    # editor = 'subl -w -n' for example 
    tmpfile.seek(0)
    print tmpfile.read()

...打开我的Sublime Text但是当我输入内容并关闭文件时，我没有输出也没有错误，只是一个空行（在Python 2上）。是的，程序确实等到我写完了。

编辑：
我刚刚发现它可能是Sublime Text特有的问题，因为vi，emacs和nano在作为编辑器输入时都能正常工作。但我仍然想知道如何解决这个问题。

Answer 1

根据＆＃34;编辑＆＃34;部分，你可以保存文件，然后重新打开它，这可能不是最好的解决方案，它不会解决＆＃34;最初的问题，但至少应该有效：

import subprocess
import tempfile

editor = ['gedit']

with tempfile.NamedTemporaryFile(delete=False) as tmpfile:
    subprocess.call(editor + [tmpfile.name])    # editor = 'subl -w -n' for example 
    tmpfile.file.close()
    tmpfile = file(tmpfile.name)
    print tmpfile.read()

Answer 2

如果直接写入输出文件，它的工作原理如下：

#!/usr/bin/env python
import subprocess
import sys
import tempfile

editor = [sys.executable, '-c', "import sys;"
                                "open(sys.argv[1], 'w').write('abc')"]
with tempfile.NamedTemporaryFile() as file:
    subprocess.check_call(editor + [file.name])
    file.seek(0)
    print file.read() # print 'abc'

如果编辑器首先写入自己的临时文件并在结尾重命名它，则失败：

#!/usr/bin/env python
import subprocess
import sys
import tempfile

editor = [sys.executable, '-c', r"""import os, sys, tempfile
output_path = sys.argv[1]
with tempfile.NamedTemporaryFile(dir=os.path.dirname(output_path),
                                 delete=False) as file:
    file.write(b'renamed')
os.rename(file.name, output_path)
"""]
with tempfile.NamedTemporaryFile() as file:
    subprocess.check_call(editor + [file.name])
    file.seek(0)
    print file.read() #XXX it prints nothing (expected 'renamed')

将文件重新打开为@Vor suggested有助于：

#!/usr/bin/env python
import os
import subprocess
import sys
import tempfile

editor = [sys.executable, '-c', r"""import os, sys, tempfile
output_path = sys.argv[1]
with tempfile.NamedTemporaryFile(dir=os.path.dirname(output_path),
                                 delete=False) as file:
    file.write(b'renamed')
os.rename(file.name, output_path)
"""]
try:
    with tempfile.NamedTemporaryFile(delete=False) as file:
        subprocess.check_call(editor + [file.name])
    with open(file.name) as file:
        print file.read() # print 'renamed'
finally:
    os.remove(file.name)

从tempfile读取的Python不成功

2 个答案: