我有一个如下所示的视图层次结构:
GridView{id=2131362110, res-name=item_list_grid,
|
+----->RelativeLayout{id=2131362124, res-name=item_image_thumb_layout
|
+------------->ImageView{id=2131362125, res-name=item_image
|
+----->RelativeLayout{id=2131362124, res-name=item_image_thumb_layout
|
+------------->ImageView{id=2131362125, res-name=item_image
|
+------>RelativeLayout{id=2131362124, res-name=item_image_thumb_layout
|
+------------->ImageView{id=2131362125, res-name=item_image
|
GridView{id=2131362110, res-name=item_list_grid, ...etc
我想点击其中一个带有id = item_image的ImageView。
我不能像onPosition(x)一样使用onView,所以我使用了onData。我尝试了所有这些:
onData(allOf(anything(),withId(R.id.item_image))).atPosition(0).perform(click());
onData(anything()).atPosition(0).perform(click());
onData(allOf(atPosition(0),withId(R.id.item_image))).perform(click());
但所有结果都是
android.support.test.espresso.AmbiguousViewMatcherException: 'is assignable from class: class android.widget.AdapterView' matches multiple views in the hierarchy.
对此有何建议?谢谢!
答案 0 :(得分:17)
您的错误消息告诉您,您的活动中有多个观看点已扩展为AdapterView
,因此您的布局中还有另一个ListView
或GridView
。
您可以选择数据层上的AdapterView
。因此,请使用AdapterView
ItemModel
onData(is(instanceOf(ItemModel.class))).atPosition(0)
.onChildView(withId(R.id.item_image)).perform(click());
或者您可以按ID
选择特定的AdapterView
onData(anything()).inAdapterView(withId(R.id.my_grid_view)).atPosition(0).
onChildView(withId(R.id.item_image)).perform(click());