所以我对此非常陌生。我正在关注网络上的一个教程,该教程展示了如何连接这两个。但是我所做的一切都只是为了抓住一部分,它说“没有联系”#34;我错过了什么?我还连接到http服务器以使用PHP脚本从数据库中查询用户名和密码。
try
{
nameValuePairs = new ArrayList<NameValuePair>();
nameValuePairs.add(new BasicNameValuePair("username", username));
nameValuePairs.add(new BasicNameValuePair("password", password));
httpPost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
response = httpClient.execute(httpPost);
if(response.getStatusLine().getStatusCode()==200)
{
entity = response.getEntity();
if(entity != null)
{
InputStream instream = entity.getContent();
JSONObject jsonResponse = new JSONObject(instream.toString());
String retUser = jsonResponse.getString("upime");
String retPass = jsonResponse.getString("geslo");
if(username.equals(retUser) && password.equals(retPass))
{
SharedPreferences sp = getSharedPreferences("logindetails", 0);
SharedPreferences.Editor spedit = sp.edit();
spedit.putString("upime", username);
spedit.putString("geslo", password);
spedit.commit();
Toast.makeText(getBaseContext(), "Login successful", Toast.LENGTH_SHORT).show();
}
else
{
Toast.makeText(getBaseContext(), "Failed to login", Toast.LENGTH_SHORT).show();
}
}
}
} catch (Exception e) {
e.printStackTrace();
Toast.makeText(getBaseContext(), "No connection", Toast.LENGTH_LONG).show();
}
答案 0 :(得分:0)
您必须创建编写php代码的webservice。网络服务可以是肥皂和休息。你必须在http客户端对象中写下webservice的URL。
通过这样做,你可以连接android和mysql。
HttpPost postD=new HttpPost("url");
答案 1 :(得分:0)
您是否在Android清单中提供了Internet权限?
<uses-permission android:name="android.permission.INTERNET" />
答案 2 :(得分:0)
<?php
header('Content-Type: application/json');
$dbhost ="localhost";
$dbuser = "username";
$dbpass = "password";
$dbdb = "db";
$connect = mysql_connect($db_host, $dbuser, $dbpass) or die("connection error");
mysql_select_db($dbdb);
$username =$_POST['username'];
$password=$_POST['password'];
$query = mysql_query("SELECT * FROM users WHERE user='$username' AND pass='$password'");
$num = mysql_num_rows($query);
if($num == 1)
{
while($list=mysql_fetch_assoc($query))
{ $output = $list;
}
mysql_close();
echo json_encode($output);
?>
将最终的&#34; echou&#34; 编辑为 echo 并添加
header('Content-Type: application/json');