我目前遇到一些使用GD调整图像大小的问题。
一切正常,直到我想要调整动画gif的大小,在黑色背景上提供第一帧。
我尝试过使用getimagesize
,但这只会给我尺寸,而不能区分任何gif和动画。
动画GIF不需要实际调整大小,只要能够跳过它们就足够了。
任何线索?
PS。我无法访问imagemagick。
亲切的问候,
克里斯
答案 0 :(得分:38)
在寻找同一问题的解决方案时,我注意到php.net网站对Davide和Kris所指的代码进行了跟进,但据作者称,内存密集程度较低,可能更少磁盘密集型。
我会在这里复制它,因为它可能是有意义的。
来源:http://www.php.net/manual/en/function.imagecreatefromgif.php#88005
function is_ani($filename) {
if(!($fh = @fopen($filename, 'rb')))
return false;
$count = 0;
//an animated gif contains multiple "frames", with each frame having a
//header made up of:
// * a static 4-byte sequence (\x00\x21\xF9\x04)
// * 4 variable bytes
// * a static 2-byte sequence (\x00\x2C)
// We read through the file til we reach the end of the file, or we've found
// at least 2 frame headers
while(!feof($fh) && $count < 2) {
$chunk = fread($fh, 1024 * 100); //read 100kb at a time
$count += preg_match_all('#\x00\x21\xF9\x04.{4}\x00[\x2C\x21]#s', $chunk, $matches);
}
fclose($fh);
return $count > 1;
}
答案 1 :(得分:18)
imagecreatefromgif()
函数的PHP手册页中有一段简短的代码片段,应该是您所需要的:
答案 2 :(得分:7)
这是工作职能:
/**
* Thanks to ZeBadger for original example, and Davide Gualano for pointing me to it
* Original at http://it.php.net/manual/en/function.imagecreatefromgif.php#59787
**/
function is_animated_gif( $filename )
{
$raw = file_get_contents( $filename );
$offset = 0;
$frames = 0;
while ($frames < 2)
{
$where1 = strpos($raw, "\x00\x21\xF9\x04", $offset);
if ( $where1 === false )
{
break;
}
else
{
$offset = $where1 + 1;
$where2 = strpos( $raw, "\x00\x2C", $offset );
if ( $where2 === false )
{
break;
}
else
{
if ( $where1 + 8 == $where2 )
{
$frames ++;
}
$offset = $where2 + 1;
}
}
}
return $frames > 1;
}
答案 3 :(得分:2)
如果给定文件太大,使用file_get_contents
读取整个文件可能会占用太多内存。我重新考虑了之前给出的函数,它只读取足够的字节来检查帧,并在找到至少2帧后立即返回。
<?php
/**
* Detects animated GIF from given file pointer resource or filename.
*
* @param resource|string $file File pointer resource or filename
* @return bool
*/
function is_animated_gif($file)
{
$fp = null;
if (is_string($file)) {
$fp = fopen($file, "rb");
} else {
$fp = $file;
/* Make sure that we are at the beginning of the file */
fseek($fp, 0);
}
if (fread($fp, 3) !== "GIF") {
fclose($fp);
return false;
}
$frames = 0;
while (!feof($fp) && $frames < 2) {
if (fread($fp, 1) === "\x00") {
/* Some of the animated GIFs do not contain graphic control extension (starts with 21 f9) */
if (fread($fp, 1) === "\x2c" || fread($fp, 2) === "\x21\xf9") {
$frames++;
}
}
}
fclose($fp);
return $frames > 1;
}
答案 4 :(得分:0)
这是对当前最高投票答案的改进,但我还没有足够的声誉来发表评论。该答案的问题在于它以100Kb块的形式读取文件,并且帧标记的末尾可能在2个块之间分割。解决这个问题的方法是将前一帧的最后20b添加到下一帧:
<?php
function is_ani($filename) {
if(!($fh = @fopen($filename, 'rb')))
return false;
$count = 0;
//an animated gif contains multiple "frames", with each frame having a
//header made up of:
// * a static 4-byte sequence (\x00\x21\xF9\x04)
// * 4 variable bytes
// * a static 2-byte sequence (\x00\x2C) (some variants may use \x00\x21 ?)
// We read through the file til we reach the end of the file, or we've found
// at least 2 frame headers
$chunk = false;
while(!feof($fh) && $count < 2) {
//add the last 20 characters from the previous string, to make sure the searched pattern is not split.
$chunk = ($chunk ? substr($chunk, -20) : "") . fread($fh, 1024 * 100); //read 100kb at a time
$count += preg_match_all('#\x00\x21\xF9\x04.{4}\x00(\x2C|\x21)#s', $chunk, $matches);
}
fclose($fh);
return $count > 1;
}
答案 5 :(得分:-1)
动画GIF必须包含以下字符串
"\x21\xFF\x0B\x4E\x45\x54\x53\x43\x41\x50\x45\x32\x2E\x30"
我已经测试了几个GIF动画,看起来字符串位于文件的pos 781(找到了file_get_contents和strpos)