Question

表格数据：

NAME     RS
A        10
A        20
A        30
B        15 
B        5
B        10
C        70
C        30

预期产出：

A   -- column name
10
20
30
60  -- total of A

B
15
5
10 
30  -- total of B

C
70
30
100 -- total of C

到目前为止，我已经尝试过：

UNION ALL
选择所有数据并使用前端进行操作。

没有UNION ALL还有其他最简单的解决方案吗？

Answer 1

使用纯SQL在单个查询中执行此操作：

SELECT unnest(arr)
FROM  (
   SELECT ARRAY[name] || array_agg(rs::text) || sum(rs)::text AS arr
   FROM   tbl
   GROUP  BY name
   ) sub
ORDER  BY arr[1];

与@WingedPanther发布的内容类似，但任何名称都是干净且安全的。

返回：

或者：

WITH cte AS (
   SELECT name, sum(RS)::text AS sum_rs
   FROM   tbl
   GROUP  BY 1
   )
SELECT unicol
FROM  ( 
   SELECT name AS unicol, name AS order1, 1 AS order2 FROM cte
   UNION  ALL
   SELECT sum_rs, name, 2 FROM cte
   ) sub
ORDER  BY order1, order2;

返回：

SQL Fiddle.

或者只是从CTE发送结果，然后完成客户端。

Answer 2

试试这个

select  unnest(string_to_array( name ||','||rs||','||sum, ',')) AS elem 
from (
     select name
           ,string_agg(rs::text,',')  rs
           ,sum(rs) 
     from tbl 
     group by name
)t

如果您想在结果中使用

打印Total Of

select  unnest(string_to_array( name ||','||rs||','||sum, ',')) AS elem 
from (
     select name
           ,string_agg(rs::text,',')  rs
           ,'Total Of '||name||' '|| sum(rs) sum
     from tbl 
     group by name
)t

> SQLFIDDLE

Answer 3

不是100％肯定你之后的事情，但听起来你只是想要这个：

Select name, Sum(RS)
from sometable
group by name

Answer 4

试试这个：

DECLARE @t TABLE(Name NVARCHAR(MAX), RS INT)

INSERT INTO @t VALUES
('A', 10),
('A', 20),
('A', 30),
('B', 15),
('C', 70),
('C', 30)

使用UNION

SELECT Name, RS, 0 AS OrderBit FROM @t
UNION ALL
SELECT Name, SUM(RS) AS Total, 1 AS OrderBit FROM @t
GROUP BY Name

ORDER BY Name, OrderBit

没有联盟：

SELECT Name, SUM(RS) AS RS FROM @t 
GROUP BY GROUPING SETS((Name), (Name, RS))

SELECT语句，用于获取带有列标题的分组列的总和

4 个答案: