Question

{"5303b93":["F2424F",40.53,22.97,0,0,0,"0000","T-LGTS2","A139","-",1421675730,"","","",1,0,"UPDATE-YOUR-FR24-APP",0],  
 "5323c35":["F2424F",50.10,14.26,51,0,0,"2104","T-LKPR27","A139","",1421675730,"","","",1,0,"UPDATE-YOUR-FR24-APP",0]}

Answer 1

也许是这样的：

JSONObject jsonObj = new JSONObject(str); 
JSONArray arrayJson = jsonObj.getJSONArray("5303b93");
for (int i = 0; i < arrayJson.length(); i++) { 
  String values= arrayJson.getString(i); 
}

因为不是＆＃34; 5303b93＆＃34;第一个数组的关键？

如果要迭代忽略键的所有数组

JSONObject jsonObj = new JSONObject(str); 
Iterator it = jsonObj.keys();
while (it.hasNext()) {
  JSONArray arrayJson = jsonObj.getJSONArray((String)it.next());
  for (int i = 0; i < arrayJson.length(); i++) { 
    String values= arrayJson.getString(i); 
  }
}

Answer 2

试试这个

<强>的strings.xml

<string name="json_data">{"5303b93":["F2424F",40.53,22.97,0,0,0,"0000","T-LGTS2","A139","-",1421675730,"","","",1,0,"UPDATE-YOUR-FR24-APP",0], "5323c35":["F2424F",50.10,14.26,51,0,0,"2104","T-LKPR27","A139","",1421675730,"","","",1,0,"UPDATE-YOUR-FR24-APP",0]}</string>

JAVA代码：

JSONObject jsonObj = null;
    try {
        jsonObj = new JSONObject(getString(R.string.json_data));
        JSONArray jsonArray1 = jsonObj.getJSONArray("5303b93");
        JSONArray jsonArray2 = jsonObj.getJSONArray("5323c35");
        for(int i= 0 ; i<jsonArray1.length(); i++){
            if(jsonArray1.getString(i) != null){
                String tempStr = jsonArray1.getString(i);
                if(tempStr != null)
                    Log.i("===First Array==="+i, "==="+tempStr+"===");
            }
        }
        for(int i= 0 ; i<jsonArray2.length(); i++){
            if(jsonArray2.getString(i) != null){
                String tempStr = jsonArray2.getString(i);
                if(tempStr != null)
                    Log.i("===Second Array==="+i, "==="+tempStr+"===");
            }
        }
    } catch (JSONException e) {
        e.printStackTrace();
    }

需要帮助来解析没有Key的json文件/字符串

2 个答案: