Question

这是我的输出程序中有$将不会打印。我将使用正确的syntex作为＆＃39; $＆＃39; +但它不起作用

SELECT USERS.ID,CONCAT(USERS.FIRSTNAME,' ',USERS.LASTNAME)AS USERNAME,
     ('$'+ SUM(CPS_HISTORY.CHARGED_AMOUNT+CPS_HISTORY.TRANSACTION_FEE+CPS_HISTORY.SERVICE_CHARGE+CPS_HISTORY.COMBO_PAK_PRICE))AS REVENUE FROM USERS JOIN CPS_HISTORY ON CPS_HISTORY.SUBSCRIBER_ID = USERS.ID GROUP BY USERS.ID ORDER BY REVENUE DESC LIMIT 5;

+---------+---------------+---------+
| ID      | USERNAME      | REVENUE |
+---------+---------------+---------+
| 1803399 | Michael Rowan |     772 |
| 1697091 | NULL          |     676 |
| 1790000 | ree Green     |     626 |
| 1766654 | Jose M NUFIO  |     625 |
| 1731854 | Ashlee Durgin |     622 |
+---------+---------------+---------+
5 rows in set, 13305 warnings (0.15 sec)

concat函数的问题是：更改数据。

+---------+-----------------+---------+
| ID      | USERNAME        | REVENUE |
+---------+-----------------+---------+
| 1753814 | Joseph Hearn    | $99     |
| 1806377 | Gideon Anderson | $99     |
| 1800992 | Camryn Revitte  | $99     |
| 1802344 | Tanner Chik     | $99     |
| 1594358 | NULL            | $99     |
+---------+-----------------+---------+
5 rows in set (0.00 sec)

Answer 1

使用concat来连接值：

SELECT USERS.ID,CONCAT(USERS.FIRSTNAME,' ',USERS.LASTNAME)AS USERNAME,
     concat('$', SUM(CPS_HISTORY.CHARGED_AMOUNT+CPS_HISTORY.TRANSACTION_FEE+CPS_HISTORY.SERVICE_CHARGE+CPS_HISTORY.COMBO_PAK_PRICE))AS REVENUE 
     FROM USERS JOIN CPS_HISTORY ON CPS_HISTORY.SUBSCRIBER_ID = USERS.ID GROUP BY USERS.ID ORDER BY REVENUE DESC LIMIT 5;

Answer 2

数据不会改变，只有类型。

您按照REVENUE列进行排序，该列之前是数字，但现在，在CONCAT()之后，它是一个字符串。 $99作为字符串出现在$772之前（如果已排序DESC）。

有两种解决方案：

在您的应用程序中添加$而不是SQL，或

使用子查询，该查询在内部查询中进行数据拾取和排序，在外部查询中进行格式化。

像

这样的东西

SELECT ID, USERNAME, CONCAT('$', REVENUE) AS REVENUE FROM
    (SELECT USERS.ID,CONCAT(USERS.FIRSTNAME,' ',USERS.LASTNAME) AS USERNAME,
    SUM(CPS_HISTORY.CHARGED_AMOUNT+CPS_HISTORY.TRANSACTION_FEE+CPS_HISTORY.SERVICE_CHARGE+CPS_HISTORY.COMBO_PAK_PRICE)) AS REVENUE
    FROM USERS JOIN CPS_HISTORY ON CPS_HISTORY.SUBSCRIBER_ID = USERS.ID
    GROUP BY USERS.ID ORDER BY REVENUE DESC LIMIT 5) AS INNER

应该这样做。（未测试！）

如何将$连接到特定字符串

2 个答案: