我尝试使用searchController进行过滤。我在以下代码中的-[__NSArrayI length]: unrecognized selector sent to instance
行遇到了崩溃(NSRange productNameRange = NSMakeRange(0, [[_list valueForKey:@"name"] length]);
):
-(void)updateFilteredContent:(NSString*)searchText {
// Update the filtered array based on the search text and scope.
[self.searchResults removeAllObjects];
// Filter the array using NSPredicate
NSLog(@"_categories are %@",_categories);
for (NSDictionary *object in _categories) {
NSUInteger searchOptions = NSCaseInsensitiveSearch | NSDiacriticInsensitiveSearch;
NSRange productNameRange = NSMakeRange(0, [[_list valueForKey:@"name"] length]);
NSRange foundRange = [[_list valueForKey:@"name"] rangeOfString:searchText options:searchOptions range:productNameRange];
if (foundRange.length > 0) {
[self.searchResults addObject:object];
}
}
}
我尝试在if ([[object valueForKey:@"name"] length] >0){
之类的长度上添加if语句,但它仍然崩溃。
_list的日志示例是:
_list names are (
"Honda",
"Ford",
Toyota,
答案 0 :(得分:0)
你的[_list valueForKey:@" name"]返回一个NSarray,它应该是一个NSString来计算它的长度..
答案 1 :(得分:0)
请检查此情况,并告诉我它是否仍然崩溃!
if([_list allkeys] contains @"name"])
{
NSString *tempStr = [_list valueForKey:@"name"];
}
if(tempStr)
NSRange productNameRange = NSMakeRange(0, [tempStr length]);