Question

我正在开发一个项目，为移动设备启用django rest框架身份验证。我正在使用默认令牌身份验证从发送用户名和密码的发布请求中获取用户令牌。

curl --data "username=username&password=password" http://127.0.0.1:8000/api/api-token-auth/

（api / api-token-auth /是使用obtain_auth_token视图配置的url）

urlpatterns = [
    url(r'^api/api-token-auth/', obtain_auth_token),
    url(r'^', include(router.urls)),
]

，响应是用户令牌。

{"token":"c8a8777aca969ea3a164967ec3bb341a3495d234"}

我需要在帖子上使用电子邮件密码而不是用户名密码或两者来获取用户令牌身份验证。我正在阅读自定义身份验证http://www.django-rest-framework.org/api-guide/authentication/#custom-authentication的文档......但实际上，对我来说并不是很清楚。这对我很有帮助...谢谢:)。

Answer 1

好的，我找到了使用电子邮件或用户名获取身份验证令牌的方法......这是序列化程序：

class AuthCustomTokenSerializer(serializers.Serializer):
    email_or_username = serializers.CharField()
    password = serializers.CharField()

    def validate(self, attrs):
        email_or_username = attrs.get('email_or_username')
        password = attrs.get('password')

        if email_or_username and password:
            # Check if user sent email
            if validateEmail(email_or_username):
                user_request = get_object_or_404(
                    User,
                    email=email_or_username,
                )

                email_or_username = user_request.username

            user = authenticate(username=email_or_username, password=password)

            if user:
                if not user.is_active:
                    msg = _('User account is disabled.')
                    raise exceptions.ValidationError(msg)
            else:
                msg = _('Unable to log in with provided credentials.')
                raise exceptions.ValidationError(msg)
        else:
            msg = _('Must include "email or username" and "password"')
            raise exceptions.ValidationError(msg)

        attrs['user'] = user
        return attrs

在email_or_username字段中，用户可以发送电子邮件或用户名，并使用功能validateEmail()，我们可以检查用户是否尝试使用电子邮件或用户名登录。然后，我们可以进行查询以获取用户实例（如果有效），并对其进行身份验证。

这是观点。

class ObtainAuthToken(APIView):
    throttle_classes = ()
    permission_classes = ()
    parser_classes = (
        parsers.FormParser,
        parsers.MultiPartParser,
        parsers.JSONParser,
    )

    renderer_classes = (renderers.JSONRenderer,)

    def post(self, request):
        serializer = AuthCustomTokenSerializer(data=request.data)
        serializer.is_valid(raise_exception=True)
        user = serializer.validated_data['user']
        token, created = Token.objects.get_or_create(user=user)

        content = {
            'token': unicode(token.key),
        }

        return Response(content)

然后：

curl --data "email_or_username=emailorusername&password=password" http://127.0.0.1:8000/api/my-api-token-auth/.

已经准备好了。

Answer 2

例如在 auth / serializers.py

中更改库使用的默认序列化程序

from django.contrib.auth import authenticate
from django.utils.translation import gettext_lazy as _

from rest_framework import serializers


class MyAuthTokenSerializer(serializers.Serializer):
    email = serializers.EmailField(label=_("Email"))
    password = serializers.CharField(
        label=_("Password",),
        style={'input_type': 'password'},
        trim_whitespace=False
    )

    def validate(self, attrs):
        email = attrs.get('email')
        password = attrs.get('password')

        if email and password:
            user = authenticate(request=self.context.get('request'),
                                email=email, password=password)

            # The authenticate call simply returns None for is_active=False
            # users. (Assuming the default ModelBackend authentication
            # backend.)
            if not user:
                msg = _('Unable to log in with provided credentials.')
                raise serializers.ValidationError(msg, code='authorization')
        else:
            msg = _('Must include "username" and "password".')
            raise serializers.ValidationError(msg, code='authorization')

        attrs['user'] = user
        return attrs

覆盖，例如 auth / views.py

中的视图

from rest_framework.authtoken import views as auth_views
from rest_framework.compat import coreapi, coreschema
from rest_framework.schemas import ManualSchema

from .serializers import MyAuthTokenSerializer


class MyAuthToken(auth_views.ObtainAuthToken):
    serializer_class = MyAuthTokenSerializer
    if coreapi is not None and coreschema is not None:
        schema = ManualSchema(
            fields=[
                coreapi.Field(
                    name="email",
                    required=True,
                    location='form',
                    schema=coreschema.String(
                        title="Email",
                        description="Valid email for authentication",
                    ),
                ),
                coreapi.Field(
                    name="password",
                    required=True,
                    location='form',
                    schema=coreschema.String(
                        title="Password",
                        description="Valid password for authentication",
                    ),
                ),
            ],
            encoding="application/json",
        )


obtain_auth_token = MyAuthToken.as_view()

例如在 auth / urls.py

中查找网址

from .views import obtain_auth_token
urlpatterns = [
    re_path(r'^api-token-auth/', obtain_auth_token),
]

您就可以出发了！

Answer 3

将这些要求写入settings.py

ACCOUNT_AUTHENTICATION_METHOD = 'email'
ACCOUNT_EMAIL_REQUIRED = True
ACCOUNT_USERNAME_REQUIRED = False

要检查，请将此json格式请求发送到您的服务器：

{
    "username":"youremail@mail.domain",
    "password":"Pa$$w0rd"
}

Answer 4

有一种更简洁的方法来获取用户令牌。

只需运行manage.py shell

然后

from rest_framework.authtoken.models import Token
from django.contrib.auth.models import User
u = User.objects.get(username='admin')
token = Token.objects.create(user=u)
print token.key

Django休息框架：使用电子邮件而不是用户名来获取身份验证令牌

4 个答案: