从循环打印结果

时间:2015-01-20 21:26:22

标签: python-2.7 loops

我目前有一段代码可以分为两部分。第一个段从本地驱动器上的特定路径打开现有文本文件,然后根据某些索引将其排列到子列表列表中。在第二个段中,我采用我创建的子列表并将它们分组在类似的索引上以简化它们(从def merge_subs开始)。我没有得到错误代码,但是当我尝试打印变量答案时,我没有收到结果。我没有正确循环原始的子列表列表吗?最后,我希望有一个包含这些循环的最终产品的变量,以便我可以将其内容写入新的文本文件。这是我正在使用的代码:

from itertools import groupby, chain
from operator import itemgetter
with open ("somepathname") as g:
    # reads text from lines and turns them into a list sub-lists
    lines = g.readlines()
    for line in lines:
        matrix = line.split()
        JD = matrix [2]
        minTime= matrix [5]
        maxTime= matrix [7]
        newLists = [JD,minTime,maxTime]
        L = newLists

def merge_subs(L):
    dates = {}
    for sub in L:
        date = sub[0]
        if date not in dates:
            dates[date] = []
        dates[date].extend(sub[1:])
    answer = []
    for date in sorted(dates):
        answer.append([date] + dates[date])

新代码

def openfile(self):
    filename = askopenfilename(parent=root)
    self.lines = open(filename)




def simplify(self):
    g = self.lines.readlines()
    for line in g:
        matrix = line.split()
        JD = matrix[2]
        minTime = matrix[5]
        maxTime = matrix[7]
        self.newLists = [JD, minTime, maxTime]
        print(self.newLists)
    dates = {}
    for sub in self.newLists:
        date = sub[0]
    if date not in dates:
        dates[date] = []
        dates[date].extend(sub[1:])
    answer = []

    for date in sorted(dates):
        print(answer.append([date] + dates[date]))

enter code here

在这里输入代码

0 个答案:

没有答案