Question

我有一个很大的CSV文件（5Go）。标题是：

run number,export,downerQ,coefUpQuality,chooseMode,demandF,nbPLots,standarDevPop,nbCitys,whatWord,priceMaxWineF,marketColor,[step],giniIndexReserve,giniIndexPatch,meanQualityTotal,meanQualityMountain,meanQualityPlain,DiffExtCentral,nbcentralPlots,meanPatchByNetwork,sum_q_viti_moutain,sum_q_viti_plaine
"3","false","0.5","0.01","false","7000","10","2","10","0","70","false","0","0","0.07083333333333335","0","0","0","0","0","0","48","0"
"4","false","0.5","0.01","false","7000","10","2","10","0","70","false","0","0","0.04285714285714286","0","0","0","0","0","0","42","0"
"2","false","0.5","0.01","false","7000","10","2","10","0","70","false","0","0","0.05348837209302328","0","0","0","0","0","0","43","0"

我想只保留包含＆＃34; 500＆＃34;在现场[步骤]（第十三场）。

我尝试在sqlite中导入此CSV ...但删除崩溃...
R也崩溃了（即使是来自data.table的fread）

是否有人使用sed，awk或任何其他命令等工具获得解决方案？

Answer 1

awk似乎要走了：

awk -F, 'NR == 1 || $13 == "\"500\""' filename

NR == 1保留第一行（标题）的位置，之后只有第13个字段为"500"的行。

使用bash中的列条件删除CSV文件中的行

1 个答案: