正则表达式 - 如何匹配空格并用冒号替换它

Question

文字看起来像这样：

816 Organizational Relationships
832 Price/Sales Catalog
846 Inventory Inquiry/Advice
850 Purchase Order
855 Purchase Order Acknowledgment

我需要用,

替换第一个空格

谢谢

Answer 1

用逗号替换任何第一个类似空格的字符（例如制表符或空格）（如果您确实需要冒号，请将,替换为:：

/\s/,/

（注意缺少g标志）

示例Bash运行：

$> echo '816 Organizational Relationships
> 832 Price/Sales Catalog
> 846 Inventory Inquiry/Advice
> 850 Purchase Order
> 855 Purchase Order Acknowledgment' | sed -e 's/\s/,/'

816,Organizational Relationships
832,Price/Sales Catalog
846,Inventory Inquiry/Advice
850,Purchase Order
855,Purchase Order Acknowledgment
$>