Question

我准备了一个小拉请求，从DB中提取今日约会：

$getAppointmentsToday = $db->prepare("SELECT * FROM appointments WHERE DATE(appointment_date) = CURDATE()");

$getAppointmentsToday->execute();

我尝试修改此语句以在接下来的7天内拉出约会，但遇到了一些麻烦：

$getAppointmentsWeek = $db->prepare("SELECT * FROM appointments WHERE DATE(appointment_date) = (CURDATE(), INTERVAL 7 DAYS)");

$getAppointmentsWeek->execute();

Answer 1

您现在正在检查日期CURDATE（）+ 7天，而不是日期间隔。使用：

SELECT * FROM appointments WHERE DATE(appointment_date) <= (CURDATE(), INTERVAL 7 DAYS) AND DATE(appointment_date) >= CURDATE()

Answer 2

您可以使用BETWEEN运算符：

... 
WHERE DATE(appointment_date) 
    BETWEEN CURDATE() 
    AND CURDATE() + INTERVAL 7 DAY

如何在CURDATE + 7天INTERVAL中提取一周的约会价值

2 个答案: