Question

此SQL在MS SQL Server上正常工作但产生错误“ORA-00907：缺少右括号”。

SQL：

UPDATE DELIVERY
SET VISIBLE = 0
WHERE DELIVERY.ID
IN 
(
    SELECT DELIVERY.ID FROM delivery WHERE DELIVERY.VISIBLE = 1
    EXCEPT
        SELECT DELIVERY.ID FROM delivery LEFT JOIN inventory ON INVENTORY.DELIVERYID = DELIVERY.ID
            WHERE ((DELIVERY.VISIBLE = 1) AND (INVENTORY.VISIBLE = 1)) AND (INVENTORY.INVENTORYSTATE = 3)
);

有没有办法让这个在Oracle上运行，或者是一个使用IN和SELECT语句的UPDATE在概念上是错误的？

Answer 1

在Oracle中，IN也可以工作，只需在Oracle中将EXCEPT更改为MINUS即可 http://www.techonthenet.com/sql/update.php

http://docs.oracle.com/cd/B19306_01/server.102/b14200/statements_10007.htm

http://docs.oracle.com/cd/E17952_01/refman-5.0-en/exists-and-not-exists-subqueries.html

此示例示例

UPDATE DELIVERY
SET VISIBLE = 0
WHERE DELIVERY.ID
IN 
(
    (SELECT DELIVERY.ID FROM delivery WHERE DELIVERY.VISIBLE = 1)
    MINUS
    (SELECT DELIVERY.ID 
    FROM delivery LEFT JOIN inventory ON INVENTORY.DELIVERYID = DELIVERY.ID
    WHERE (((DELIVERY.VISIBLE = 1) AND (INVENTORY.VISIBLE = 1)) 
          AND (INVENTORY.INVENTORYSTATE = 3)))
);

Answer 2

我认为您可以修改此查询，以便它在SQL Server 和 Oracle中都有效：

UPDATE delivery d
   SET d.visible = 0
 WHERE d.visible = 1
   AND NOT EXISTS ( SELECT 1 FROM inventory i
                     WHERE i.deliveryid = d.id
                       AND i.visible = 1
                       AND i.inventorystate = 3 )

这会在DELIVERY = 1的任何地方更新visible设置visible = 0，但INVENTORY中visible = 1和{{{{}}中没有相应的记录1}} = 3。

使用IN SELECT的Oracle vs MS SQL UPDATE

2 个答案: