基于archetype我创建了一个java ee应用程序。有一个包括arquillian测试运行正常。它只是在@Stateless bean上调用一个持久化实体的方法。
现在我添加了一些实体与一些关系,我为他们写了一个测试。但是在坚持任何实体我得到
Transaction is required to perform this operation (either use a transaction or extended persistence context)
我认为我需要用@Transactional来标记testmethod,但它似乎不是在类路径中。 在注入的EntityManager上手动调用事务会产生另一个错误。 那么如何正确设置这样的测试和依赖。
编辑正如Grzesiek D.在此提出的一些细节。这是实体(与其他人联系):
@Entity
public class Booking implements Serializable {
/**
*
*/
private static final long serialVersionUID = 1L;
/**
* internal id.
*/
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
@Column(name = "id", updatable = false, nullable = false)
private Long id;
/**
* Used for optimistic locking.
*/
@Version
@Column(name = "version")
private int version;
/**
* A booking must have a project related.
*/
@ManyToOne
@JoinColumn(name = "project_id")
@NotNull
private Project project;
/**
* A booking must have an owner.
*/
@ManyToOne
@JoinColumn(name = "user_id")
@NotNull
private User owner;
/**
* A booking always has a start time.
*/
@Column
@NotNull
private Timestamp start;
/**
* A booking always has an end time.
*/
@Column
@NotNull
private Timestamp end;
/**
*
* @return true if start is befor end. false otherwise (if equal or after end).
*/
@AssertTrue(message = "Start must before end.")
public final boolean isStartBeforeEnd() {
return start.compareTo(end) < 0;
}
/**
* @return the id
*/
public final Long getId() {
return id;
}
/**
* @param id
* the id to set
*/
public final void setId(final Long id) {
this.id = id;
}
/**
* @return the version
*/
public final int getVersion() {
return version;
}
/**
* @param version
* the version to set
*/
public final void setVersion(final int version) {
this.version = version;
}
/**
* @return the project
*/
public final Project getProject() {
return project;
}
/**
* @param project
* the project to set
*/
public final void setProject(final Project project) {
this.project = project;
}
/**
* @return the owner
*/
public final User getOwner() {
return owner;
}
/**
* @param owner
* the owner to set
*/
public final void setOwner(final User owner) {
this.owner = owner;
}
/**
* @return the start
*/
public final Timestamp getStart() {
return start;
}
/**
* @param start
* the start to set
*/
public final void setStart(final Timestamp start) {
this.start = start;
}
/**
* @return the end
*/
public final Timestamp getEnd() {
return end;
}
/**
* @param end
* the end to set
*/
public final void setEnd(final Timestamp end) {
this.end = end;
}
//hashCode, equals, toString omitted here
}
以下是测试:
@RunWith(Arquillian.class)
public class BookingTest {
@Deployment
public static Archive<?> createDeployment() {
return ArquillianContainer.addClasses(Resources.class, Booking.class, Project.class, User.class);
}
@Inject
private EntityManager em;
@Test
public void createBooking() {
Booking booking = new Booking();
booking.setStart(new Timestamp(0));
booking.setEnd(new Timestamp(2));
User user = new User();
user.setName("Klaus");
booking.setOwner(user);
Project project = new Project();
project.setName("theOne");
project.setDescription("blub");
booking.setProject(project);
em.persist(booking);
System.out.println("here");
}
}
这里有例外:
javax.persistence.TransactionRequiredException: JBAS011469: Transaction is required to perform this operation (either use a transaction or extended persistence context)
我知道如果我创建一个@Stateless bean并在那里封装持久化,但我想直接测试实体的验证,我需要一个操场来改进数据模型。
答案 0 :(得分:10)
为了在Arquillian测试中获得交易支持,您需要引入extension which enables this feature。在你的情况下jta
依赖应该做的工作。
<dependency>
<groupId>org.jboss.arquillian.extension</groupId>
<artifactId>arquillian-transaction-jta</artifactId>
<scope>test</scope>
</dependency>
&#13;
此外,如果您使用JBoss,则需要为UserTranscation
提供其JNDI,因此请在arquillian.xml
中添加以下部分:
<?xml version="1.0" ?>
<arquillian xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://jboss.org/schema/arquillian" xsi:schemaLocation="http://jboss.org/schema/arquillian
http://jboss.org/schema/arquillian/arquillian_1_0.xsd">
<extension qualifier="transaction">
<property name="manager">java:jboss/UserTransaction</property>
</extension>
</arquillian>
这样您就可以使用来自此扩展程序API的@Transactional
。