Question

我希望从存储过程中返回每个部门的前四名最高工资以及deptno和dname。当deptno不包括在内时没有错误但是当包括deptno我得到一个错误无效的数字。 ORA-01722：无效的号码这是代码

    create or replace procedure tpro2(dno in emp.deptno%type,dnum out dept.deptno%type, name out emp.ename%type, sal out emp.sal%type,dname out dept.dname%type, cur out sys_refcursor)
    is begin
    open cur for select ename , sal, dname, dept.deptno from (select * from emp order by sal desc)emp, dept where emp.deptno=dept.deptno and emp.deptno=dno and rownum<=4;
    end tpro2;
    /

   declare
   dnum dept.deptno%type;
   name emp.ename%type;
   sal emp.sal%type;
   dname dept.dname%type;
   cur sys_refcursor;
   begin
   tpro2(&dno,dnum,name,sal,dname,cur);
   loop
   fetch cur into dnum,name,sal,dname;
   exit when cur%notfound;
   dbms_output.put_line(dnum||'  '||name||'  '||sal||'  '||dname);
   end loop;
   close cur;
   end;
   /

请帮助!!!

Answer 1

open cur for select ename, sal, dname, dept.deptno 
fetch cur into dnum, name, sal, dname;

你觉得这里没有什么可疑的吗？：）

Answer 2

我会使用window functions来获取您需要的信息，而无需编写存储过程：

SELECT ename, sal, dname, deptno
       RANK() OVER (PARTITION BY deptno ORDER BY sal DESC) "Rank"
  FROM emp e inner join dept d using (deptno)

我希望从存储过程中返回每个部门的前四名最高工资以及deptno和dname

2 个答案: