PHP如何在mysql中逐步增加日期

Question

我每天都要运行一堆任务，应该在同一天完成。所以，我想检查这些任务是否在同一天完成。

$sql = "SELECT date, MIN(date), MAX(date) FROM task_scheduler 
WHERE (date >= $date  AND date < $date_plus_1day)";

我们说我需要查看以下日期。

$min_date = '2014-12-30';
$max_date = '2015-01-03';

如何获得PHP中给出的日期的每日报告，如下例所示：

date        MIN(date)    MAX(date)
2014-12-30  2014-12-30   2014-12-31 (didn't complete on same day)
2014-12-31  2014-12-31   2014-12-31 (completed on same day)
2015-01-01  2015-01-01   2015-01-01 (completed on same day)
2015-01-02  2015-01-02   2015-01-03 (didn't complete on same day)
2015-01-03  2015-01-03   2015-01-05 (didn't complete on same day)

Answer 1

使用HAVING子句。它适用于应用聚合函数后。

...
WHERE ...
HAVING MAX(date) = MIN(date) + INTERVAL 1 DAY;