Question

private static void algorithm2() {
    String name = "";
    int high = (char)90;
    int low =(char) 66;
    int letter;
    int direction;  
    do {
        letter = (high + low) / 2;
        String[] choices = { "Before", "This is the letter", "After", "Done" }; 

        direction = JOptionPane.showOptionDialog(null,
                "Is the next letter in your name a(n) \'" +(char) letter
                        + "\' or is it after/before it? ", "Option 2",
                JOptionPane.DEFAULT_OPTION,
                JOptionPane.PLAIN_MESSAGE,
                null, choices, "Option 2");

        if (direction == 0)
            low= letter - 1; // 

        if (direction == 1){
            name+=(char)letter;
        }

        if(direction==2){
            high = letter + 1; // last guess was too high
        }
        if (direction == 3)
            break;
    } while (direction != 1);

    JOptionPane.showMessageDialog(null, "Thanks for playing " + name + "!");
}

猜猜每个可能字母序列中的中间字母。第一次，这是m或n。每当做出猜测时，询问用户a）猜测是否正确，b）正确答案的字母顺序早于猜测，或c）正确的字母后来按字母顺序而不是猜测。相应地调整后续猜测，总是猜测剩余的可能字母组中的中间字母。当可能性的数量是偶数时，您是否猜测第一个或第二个“中间”字母并不重要。当只有一种可能性时，那一种是一个值列表中的中间选择。

我无法使其工作，当我出现窗口时，我点击之前显示错误的字母。

Answer 1

正如人们在评论中指出的那样：

if (direction == 0)
    low= letter - 1; //

应该是

high = letter - 1;

同样，

if(direction==2){
   high = letter + 1; // last guess was too high
}

应该是

low = letter + 1;

此外，当direction == 1终止循环时：

while (direction != 1);

因此用户无法填写超过1个字符，因此您应将其更改为while(true);或while(direction != 3)

public static void main(String[] args) {


    String name = "";
    int direction;
    do {
        int high = (char) 90;
        int low = (char) 66;
        int letter;

        do {
            letter = (high + low) / 2;
            String[] choices = { "Before", "This is the letter", "After",
                    "Done" };

            direction = JOptionPane.showOptionDialog(null,
                    "Is the next letter in your name a(n) \'"
                            + (char) letter
                            + "\' or is it after/before it? ", "Option 2",
                    JOptionPane.DEFAULT_OPTION, JOptionPane.PLAIN_MESSAGE,
                    null, choices, "Option 2");
            System.out.println(direction);
            if (direction == 0)
                high = letter - 1; //

            if (direction == 1 || direction == 3) {
                name += (char) letter;
            }

            if (direction == 2) {
                low = letter + 1; // last guess was too high
            }

        } while (direction != 1 && direction != 3);

    } while (direction != 3);

    JOptionPane.showMessageDialog(null, "Thanks for playing " + name + "!");
}

high == low时要小心，如果用户不接受此字符，则应该是错误。

如何使我的方法正常工作？

1 个答案: