我有多行,我只需要选择那些包含特定值的行。 例如,
[DEBUG] 2014-12-01 16:39:12,049 [1984] Agent Logger Initialized
[DEBUG] 2014-12-01 16:39:12,049 [2884] Agent Logger Initialized
[DEBUG] 2014-12-01 16:39:12,049 [2884] Agent Actuation Logger Initialized
所以我有一个变量var = 1984。
id=re.search(r'\[var\],s,re.I|re.M|re.S)
if id:
print line
上面的正则表达式只能搜索var = 1984并且应该打印包含该值的行" [1984]"。有人建议怎么做吗?我需要这个在Linux中搜索我正在使用Python 2.6。
答案 0 :(得分:0)
这个正则表达式应该有效:
var=1984
reg = '.+'+str(var)+'.+'
id=re.search(reg,s,re.I|re.M|re.S)
或简单:
import re
s = ['[DEBUG] 2014-12-01 16:39:12,049 [1984] Agent Logger Initialized',
'[DEBUG] 2014-12-01 16:39:12,049 [2884] Agent Logger Initialized',
'[DEBUG] 2014-12-01 16:39:12,049 [2884] Agent Actuation Logger Initialized']
var = 1984
for line in s:
id = re.findall(r'.+%d.+' % var, line, re.I | re.M | re.S)
if id:
print line
输出:
[DEBUG] 2014-12-01 16:39:12,049 [1984] Agent Logger Initialized
答案 1 :(得分:0)
您也可以使用简单的if
条件来执行此操作:
from io import StringIO
text = StringIO(u"""\
[DEBUG] 2014-12-01 16:39:12,049 [1984] Agent Logger Initialized
[DEBUG] 2014-12-01 16:39:12,049 [2884] Agent Logger Initialized
[DEBUG] 2014-12-01 16:39:12,049 [2884] Agent Actuation Logger Initialized
""")
for line in text:
if '[1984]' in line:
print line
[DEBUG] 2014-12-01 16:39:12,049 [1984] Agent Logger Initialized
答案 2 :(得分:0)
这应该有效:
#!/usr/bin/env python
# -*- coding: utf-8 -*-
import re
var = '\[1984\]'
with open("test.log") as fp: # assuming your log file is test.log
lines = fp.readlines()
for line in lines:
line = line.strip()
if re.match(r'.*'+str(var)+'.*',line): # may be you want to add some more strict matching rules here.
print line
# vim:ai:et:sts=4:sw=4: