如何解雇google plus android中的初始客户经理对话框？

Question

您好我正在使用谷歌加。当我点击按钮时，它需要显示电子邮件和其他信息。但问题是如果用户有多个帐户，没有点击按钮，对话框就会打开。关闭对话框并单击按钮后，再次打开对话框并正常工作。我找不到这个奇怪的问题。 当我启动屏幕而不点击按钮时，选择一个帐户对话框正在打开。怎么解决这个问题？

这是我的代码：我正在使用片段。

 public class LoginFragment extends SherlockFragment implements   OnClickListener,
    ConnectionCallbacks, OnConnectionFailedListener {

    @Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container,
        Bundle savedInstanceState) {
    Common.mGoogleApiClient = new GoogleApiClient.Builder(getActivity())
            .addConnectionCallbacks(this)
            .addOnConnectionFailedListener(this).addApi(Plus.API)
            .addScope(Plus.SCOPE_PLUS_LOGIN).build();

    Common.mGoogleApiClient.connect();

    return view;
}
 public void onStop() {
    super.onStop();
    if (Common.mGoogleApiClient.isConnected()) {
        Common.mGoogleApiClient.disconnect();
    }
    }
    }
     Common:
     public class Common {
     static int RC_SIGN_IN = 0;
     static String TAG = "MainActivity";
     static int PROFILE_PIC_SIZE = 400;
     static GoogleApiClient mGoogleApiClient;
     static boolean mIntentInProgress;
      static boolean mSignInClicked;
      static ConnectionResult mConnectionResult;
      static Activity con;
      public Common(Activity c) {
      con = c;
       }

LoginActivity：

      public class LoginActivity extends SherlockFragmentActivity {
        @Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.login);
    public void resolveSignInError() {
    if (Common.mConnectionResult != null) {
        if (Common.mConnectionResult.hasResolution()) {
            try {
                Common.mIntentInProgress = true;
                Common.mConnectionResult.startResolutionForResult(
                        Common.con, Common.RC_SIGN_IN);
            } catch (SendIntentException e) {
                Common.mIntentInProgress = false;
                Common.mGoogleApiClient.connect();
            }
        }
    }
}
@Override
protected void onActivityResult(int requestCode, int responseCode,
        Intent data) {
    super.onActivityResult(requestCode, responseCode, data);

    if (requestCode == Common.RC_SIGN_IN) {
        if (responseCode != Common.con.RESULT_OK) {
            Common.mSignInClicked = false;
        }

        Common.mIntentInProgress = false;

        if (!Common.mGoogleApiClient.isConnecting()) {
            Common.mGoogleApiClient.connect();
        }
    }

}

}

这是截图，没有点击谷歌加按钮，弹出对话框。