Question

我在Java编程方面全新。我为Android制作了一个应用程序，根据IOIO板上4个数字输入的组合显示16张可信图片中的1张。我使用IF句子做了这个（也许这不是最好的方式但是有效），现在我的问题是：我想要不仅显示一张图片而且要显示图片（4或5）的图像以显示动画。

这样的事情：

if ((((val1 == false)&& (val2 == true)) && (val3 == true)) && (val4 == true)){
                        imagen.setImageResource(R.drawable.in1);
                        Thread.sleep(100);
                        imagen.setImageResource(R.drawable.in2);
                        Thread.sleep(100);
                        imagen.setImageResource(R.drawable.in3);
                        Thread.sleep(100);
                        imagen.setImageResource(R.drawable.in4);
                        Thread.sleep(100);
                    }

我尝试：

Thread.sleep(100);

但是当我尝试编译时出错了也可以试试：

    try {
 Thread.sleep(100);
 } catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}

但该应用程序不起作用。任何消化???

这是我的应用的代码：

package com.example.mycar;

import ioio.lib.api.DigitalInput;
import ioio.lib.api.exception.ConnectionLostException;
import ioio.lib.util.BaseIOIOLooper;
import ioio.lib.util.IOIOLooper;
import ioio.lib.util.android.IOIOActivity;
import android.os.Bundle;
import android.widget.ImageView;

public class MainActivity extends IOIOActivity {

boolean val1, val2, val3, val4;
ImageView imagen;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    imagen = (ImageView) findViewById(R.id.estado);
}

class Looper extends BaseIOIOLooper{

    DigitalInput entrada1, entrada2, entrada3, entrada4;

    @Override
    protected void setup() throws ConnectionLostException,
            InterruptedException {
        // TODO Auto-generated method stub
        entrada1 = ioio_.openDigitalInput(37, DigitalInput.Spec.Mode.PULL_UP);
        entrada2 = ioio_.openDigitalInput(38, DigitalInput.Spec.Mode.PULL_UP);
        entrada3 = ioio_.openDigitalInput(39, DigitalInput.Spec.Mode.PULL_UP);
        entrada4 = ioio_.openDigitalInput(40, DigitalInput.Spec.Mode.PULL_UP);
    }

    @Override
    public void loop() throws ConnectionLostException, InterruptedException {
        // TODO Auto-generated method stub
        val1 = entrada1.read();
        val2 = entrada2.read();
        val3 = entrada3.read();
        val4 = entrada4.read();
        mostrarentradas(val1, val2, val3, val4);
        Thread.sleep(20);
    }

}

@Override
protected IOIOLooper createIOIOLooper() {
    // TODO Auto-generated method stub
    return new Looper();
}
private void mostrarentradas(final boolean val1, final boolean val2, final boolean val3,
        final boolean val4) {
    // TODO Auto-generated method stub
    runOnUiThread(new Runnable()

            {

                @Override
                public void run() {
                    // TODO Auto-generated method stub

                    if ((((val1 == false)&& (val2 == true)) && (val3 == true)) && (val4 == true)){
                        imagen.setImageResource(R.drawable.in1);
                    }
                    if ((((val1 == false)&& (val2 == false)) && (val3 == true)) && (val4 == true)){
                        imagen.setImageResource(R.drawable.in8);
                    }
                    if ((((val1 == false)&& (val2 == false)) && (val3 == false)) && (val4 == true)){
                        imagen.setImageResource(R.drawable.in11);
                    }
                    if ((((val1 == false)&& (val2 == false)) && (val3 == false)) && (val4 == false)){
                        imagen.setImageResource(R.drawable.in14);
                    }
                    if ((((val1 == false)&& (val2 == true)) && (val3 == false)) && (val4 == true)){
                        imagen.setImageResource(R.drawable.in16);
                    }
                    if ((((val1 == false)&& (val2 == true)) && (val3 == true)) && (val4 == false)){
                        imagen.setImageResource(R.drawable.in22);
                    }
                    if ((((val1 == false)&& (val2 == false)) && (val3 == true)) && (val4 == false)){
                        imagen.setImageResource(R.drawable.in25);
                    }
                    if ((((val1 == false)&& (val2 == true)) && (val3 == false)) && (val4 == false)){
                        imagen.setImageResource(R.drawable.in29);
                    }
                    if ((((val1 == true)&& (val2 == false)) && (val3 == true)) && (val4 == true)){
                        imagen.setImageResource(R.drawable.in2);
                        //Thread.sleep(100);
                        imagen.setImageResource(R.drawable.in3);
                    }
                    if ((((val1 == true)&& (val2 == false)) && (val3 == false)) && (val4 == true)){
                        imagen.setImageResource(R.drawable.in18);
                    }
                    if ((((val1 == true)&& (val2 == false)) && (val3 == true)) && (val4 == false)){
                        imagen.setImageResource(R.drawable.in20);
                    }
                    if ((((val1 == true)&& (val2 == false)) && (val3 == false)) && (val4 == false)){
                        imagen.setImageResource(R.drawable.in27);
                    }
                    if ((((val1 == true)&& (val2 == true)) && (val3 == false)) && (val4 == true)){
                        imagen.setImageResource(R.drawable.in4);
                    }
                    if ((((val1 == true)&& (val2 == true)) && (val3 == false)) && (val4 == false)){
                        imagen.setImageResource(R.drawable.in30);
                    }
                    if ((((val1 == true)&& (val2 == true)) && (val3 == true)) && (val4 == false)){
                        imagen.setImageResource(R.drawable.in5);
                    }
                    if ((((val1 == true)&& (val2 == true)) && (val3 == true)) && (val4 == true)){
                        imagen.setImageResource(R.drawable.vwg0);
                    }

                }

            }
    );
}

}

Answer 1

可能会使用postDelayed方法和Runnable吗？为它创建分离的线程对此来说太多了，也无法更新UI外部的线程

imagen.postDelayed(new Runnable(){

    @Override
    public void run(){
        imagen.setImageResource(R.drawable.in1);
    }
}, 1000); //1000ms delay

在run内{p>您可能会再次设置postDelayed方法

Android程序如何以时间间隔显示图片？

1 个答案: