Question

我所拥有的是一个程序，它将读取一个文件，该文件包含格式为

的文件中的数据

`FootballTeamName1 : FootballTeamName2 : FootballTeam1Score : FootballTeam2Score

目前它读入文件并将它分割到每个冒号我想知道的是我如何制作它以便每次遇到一个名称然后它会将该名称添加到列表中，如果它没有＆＃39 ; t已经存在或者如果它已经存在，那么它将不会创建重复值，而是将值添加到该团队名称已存在的值。

我目前有一个程序可以获取搜索团队时的值，但我想要做的就是当用户没有指定团队时可以使用它然后它会使它成为一个团队将返回所有团队的结果。以下是我目前要求提供文件位置的信息，并要求用户指定一个有效的文件，但我不确定如何做我想做的事。

import java.awt.Desktop;
import java.io.*;
import java.util.*;

public class reader {

//used to count the number of invalid and valid matches

public static boolean verifyFormat(String[] words) {
    boolean valid = true;
    if (words.length != 4) { 
        valid = false;
    } else if (words[0].isEmpty() || words[0].matches("\\s+")) {
        valid = false;
    } else if ( words[1].isEmpty() || words[1].matches("\\s+")) {
        valid = false;
    }

    return valid && isInteger(words[2]) && isInteger(words[3]);}

//checks to see that the number of items in the file are equal to the four needed and the last 2 are integers
//also checks to make sure that there are no results that are just whitespace

public static boolean isInteger( String input ) {
    try {
        Integer.parseInt( input );
        return true;
    }
    catch( Exception e ) {
        return false;
    }
}
//checks to make sure that the data is an integer

public static void main(String[] args) throws IOException {

      Scanner sc = new Scanner(System.in);
      while(true){ //Runs until it is specified to break

            Scanner scanner = new Scanner(System.in);


        System.out.println("Enter filename");
        String UserFile = sc.nextLine();
        File file = new File(UserFile);
        if(!file.exists()) {
          continue;
        }

        if(UserFile != null && !UserFile.isEmpty()){ 
            System.out.println("Do you want to generate plain (T)ext or (H)TML");
            String input = scanner.nextLine();
            if ( input.equalsIgnoreCase("H") ) {
                processFile(UserFile)   ;           }
            else if ( input.equalsIgnoreCase("T")){
                  processFile(UserFile);
            }
                  else{
                        System.out.println("Do you want to generate plain (T)ext or (H)TML");


                    }

        }
      }
    }

//checks how the user wants the file to be displayed 

private static void processFile(String UserFile) throws FileNotFoundException {
    String hteam;
    String ateam;
    int hscore;
    int ascore;
    int totgoals = 0;
    int gamesplayed = 0;
    int gs = 0;
    int gc = 0;
    int w = 0;
    int d = 0;
    int l = 0;
    String newLine = System.getProperty("line.separator");//This will retrieve line separator dependent on OS.


    Scanner s = new Scanner(new BufferedReader(
            new FileReader(UserFile))).useDelimiter("\\s*:\\s*|\\s*\\n\\s*");

    Scanner scanner = new Scanner(System.in);

    System.out.println("Enter the name of the team you want the results for");
    String input = scanner.nextLine();


    while (s.hasNext()) {
        String line = s.nextLine();
        String[] words = line.split("\\s*:\\s*");
        //splits the file at colons

        if(verifyFormat(words)) {
            hteam = words[0];       // read the home team
            ateam = words[1];       // read the away team
            hscore = Integer.parseInt(words[2]);       //read the home team score
            totgoals = totgoals + hscore;
            ascore = Integer.parseInt(words[3]);       //read the away team score
            totgoals = totgoals + ascore;

             if ( input.equalsIgnoreCase(hteam)){
                 gamesplayed = gamesplayed + 1;
                 gs = gs + hscore;
                 gc = gc + ascore;
                 if (hscore > ascore)
                     w = w + 1;
                 else if (ascore > hscore)
                     l = l + 1;
                 else
                     d = d + 1;
             }
             else if (input.equalsIgnoreCase(ateam)){
                 gamesplayed = gamesplayed + 1;
                 gs = gs + ascore;
                 gc = gc + hscore;
                 if (hscore < ascore)
                     w = w + 1;
                 else if (ascore < hscore)
                     l = l + 1;
                 else
                     d = d + 1;
             }
        }
    }
    System.out.println(input + newLine + "--------------------------" + newLine + "Games played: " + gamesplayed +   newLine + "Games Won: " + w + newLine + "Games Drawn: " + d + newLine + "Games Lost: " + l + newLine + "Goals For: " + gs + newLine + "Goals Against: " + gc);   
}
}

Answer 1

如果您希望集合中没有重复元素，请使用Set。 Set是一个不包含重复元素的集合（doc here）。

Answer 2

您可以将条目添加到集合中（或者如果您希望它们排序 - SortedSet）。由于Set仅包含唯一值 - 您将始终只有一个＆＃34; copy＆＃34;每个值。

作为参考，以下代码使用5个值，但该集合只有3个（唯一）值：

String str = "A : B : C : B : A";
String[] vals = str.split(":");
SortedSet<String> myVals = new TreeSet<String>();
for(String val : vals)
{
    myVals.add(val.trim());
}

System.out.println("Set size: " + myVals.size());

Answer 3

听起来你想要一个团队地图得分，如果团队已经存在，那么从地图中获取值，然后得分。

从文本文件中获取值，然后将它们放入没有重复项的列表中？

3 个答案: