Question

我需要提取这些XML-Comments。特别是标准评论。我是XML-Parsing的新手。我目前正在使用标准的Java-XML-Parser javax.xml

     <criteria>
    <criteria operator="OR" comment="Operation system section">
      <extend_definition comment="SUSE Linux Enterprise Server 12 is installed" definition_ref="oval:org.mitre.oval:def:28211"/>
      <extend_definition comment="SUSE Linux Enterprise Desktop 12 is installed" definition_ref="oval:org.mitre.oval:def:28148"/>
    </criteria>
    <criterion comment="update-test-security-0 is earlier than 0:11.2" test_ref="oval:org.mitre.oval:tst:136394"/>
  </criteria>

我如何提取评论？

Answer 1

只需阅读名为＆＃34;评论＆＃34;的所有属性我建议通过XMLBeam使用XPath。（披露：我是这个项目的附属机构。）

public class ReadAttributes {
public static void main(String[] args) {
        List<String> comments = new XBProjector().io().stream(ReadAttributes.class.getResourceAsStream("data.xml")).evalXPath("//@comment").asListOf(String.class);
        System.out.println(comments);
        }
}

此程序打印出来：

[Operation system section, SUSE Linux Enterprise Server 12 is installed, SUSE Linux Enterprise Desktop 12 is installed, update-test-security-0 is earlier than 0:11.2]

Answer 2

如果您不需要将整个XML数据作为java对象并且只需要标准注释属性，则可以使用XPath来获取它：

XPath xpath = XPathFactory.newInstance().newXPath();
return xpath.evaluate("/criteria/criterion/@comment", document);

如果您在字符串中包含XML并且不知道如何将其解析为Document，请查看：How to convert XML (String) to a valid document?

Answer 3

您还可以使用JDK的简单XPath功能：

String[] args = new String[]{ "//*[@comment]" };
XPathFactory xpf = XPathFactory.newInstance();
XPath xpath = xpf.newXPath();
for( String s: args ){
    XPathExpression xpExp = xpath.compile( "count("+s+")" );
    String res = xpExp.evaluate( source );
    System.out.println( s + ": " + res );
    int n = Integer.parseInt( res );
    for( int i = 1; i <= n; i++ ){
        xpExp = xpath.compile( "(" + s + ")[" + i + "]/@comment" );
        System.out.println(  "comment: " + xpExp.evaluate( source ) );
    }
}

从具有Java的节点获取名为comment的属性

3 个答案: