我目前在SQL Server中有两个单独的查询,用于计算表在一周内包含唯一ID的次数。我想使用一个查询显示这些,而不是两个。
此数据保存在两个单独的视图中,因此我编写了两个查询。这些是ActivityPointer
和Asp_dealercallreport
。
查询#1:
SELECT
OwnerIDName,
COUNT(Distinct ActivityID) AS CalendarEvents
FROM
ActivityPointer
WHERE
/*Specify Activity code for Calendar Events*/
ActivityTypeCode = '4201'
/*Specify Calendar Events from this week only*/
AND ScheduledStart >= DATEADD(DAY, DATEDIFF(DAY, 0, GETDATE()) / 7 * 7, 0)
AND ScheduledStart <= DATEADD(DAY, DATEDIFF(DAY, -1, GETDATE()), 0)
/*Specify users to be reported on by Name*/
AND OwnerIdName IN ('John Doe', 'Jane Doe')
GROUP BY
OwnerIDName
查询#2:
SELECT
OwnerIDName,
COUNT(Distinct Asp_dealercallreportId) AS DealerVisits
FROM
Asp_dealercallreport
/*Specify Calendar Events from this week only*/
WHERE
asp_callreportdate >= DATEADD(DAY, DATEDIFF(DAY, 0, GETDATE()) / 7 * 7, 0)
AND asp_callreportdate <= DATEADD(DAY, DATEDIFF(DAY, -1, GETDATE()), 0)
/*Specify to be reported on by Name*/
AND OwnerIdName IN ('John Doe', 'Jane Doe')
GROUP BY
OwnerIDName
由于
答案 0 :(得分:1)
使用条件聚合:
SELECT OwnerIDName,
COUNT(Distinct case when ScheduledStart >= DATEADD(DAY, DATEDIFF(DAY, 0, GETDATE()) / 7 * 7, 0) AND
ScheduledStart <= DATEADD(DAY, DATEDIFF(DAY, -1, GETDATE()), 0)
then ActivityID end) AS CalendarEvents_Scheduled,
COUNT(Distinct case when asp_callreportdate >= DATEADD(DAY, DATEDIFF(DAY, 0, GETDATE()) / 7 * 7, 0) and
asp_callreportdate <= DATEADD(DAY, DATEDIFF(DAY, -1, GETDATE()), 0)
then ActivityID end) AS CalendarEvents_asp
FROM ActivityPointer
WHERE ActivityTypeCode = '4201' AND
OwnerIdName IN ('John Doe', 'Jane Doe')
GROUP BY OwnerIDName;
答案 1 :(得分:1)
也许你可以简单地使用INNER JOIN运算符?像这样:
SELECT
ap.OwnerIDName,
COUNT(Distinct ap.ActivityID) AS CalendarEvents,
COUNT(Distinct a_dcr.Asp_dealercallreportId) AS DealerVisits
FROM
ActivityPointer ap
INNER JOIN
Asp_dealercallreport a_dcr ON ap.OwnerIDName=a_dcr.OwnerIDName
WHERE
/*Specify Activity code for Calendar Events*/
ap.ActivityTypeCode = '4201'
/*Specify Calendar Events from this week only*/
AND ap.ScheduledStart >= DATEADD(DAY, DATEDIFF(DAY, 0, GETDATE()) / 7 * 7, 0)
AND ap.ScheduledStart <= DATEADD(DAY, DATEDIFF(DAY, -1, GETDATE()), 0)
/*Specify Calendar Events from this week only*/
AND a_dcr.asp_callreportdate >= DATEADD(DAY, DATEDIFF(DAY, 0, GETDATE()) / 7 * 7, 0)
AND a_dcr.asp_callreportdate <= DATEADD(DAY, DATEDIFF(DAY, -1, GETDATE()), 0)
/*Specify users to be reported on by Name*/
AND ap.OwnerIdName IN ('John Doe', 'Jane Doe')
GROUP BY
ap.OwnerIDName
答案 2 :(得分:1)
使用标准SQL UNION将在一个结果集中为您提供两个查询的输出。只要它们具有相同数量和类型的列:
http://www.w3schools.com/sql/sql_union.asp
SELECT OwnerIDName, COUNT(Distinct ActivityID) AS CalendarEvents
FROM ActivityPointer
WHERE
/*Specify Activity code for Calendar Events*/
ActivityTypeCode = '4201'
/*Specify Calendar Events from this week only*/
AND ScheduledStart >= DATEADD(DAY, DATEDIFF(DAY, 0, GETDATE()) / 7 * 7, 0)
AND ScheduledStart <= DATEADD(DAY, DATEDIFF(DAY, -1, GETDATE()), 0)
/*Specify users to be reported on by Name*/
AND OwnerIdName IN ('John Doe', 'Jane Doe')
GROUP BY OwnerIDName
UNION
SELECT OwnerIDName, COUNT(Distinct Asp_dealercallreportId) AS DealerVisits
FROM Asp_dealercallreport
/*Specify Calendar Events from this week only*/
WHERE asp_callreportdate >= DATEADD(DAY, DATEDIFF(DAY, 0, GETDATE()) / 7 * 7, 0)
AND asp_callreportdate <= DATEADD(DAY, DATEDIFF(DAY, -1, GETDATE()), 0)
/*Specify to be reported on by Name*/
AND OwnerIdName IN ('John Doe', 'Jane Doe')
GROUP BY OwnerIDName