我有这个代码,例如
http://play.golang.org/p/9U22NfrXeq
// A concurrent prime sieve
package main
// Send the sequence 2, 3, 4, ... to channel 'ch'.
func Generate(ch chan<- int) {
for i := 2; ; i++ {
ch <- i // Send 'i' to channel 'ch'.
}
}
// Copy the values from channel 'in' to channel 'out',
// removing those divisible by 'prime'.
func Filter(in <-chan int, out chan<- int, prime int) {
for {
i := <-in // Receive value from 'in'.
if i%prime != 0 {
out <- i // Send 'i' to 'out'.
}
}
}
// The prime sieve: Daisy-chain Filter processes.
func main() {
ch := make(chan int) // Create a new channel.
go Generate(ch) // Launch Generate goroutine.
for i := 0; i < 10; i++ {
prime := <-ch
print(prime, "\n")
ch1 := make(chan int)
go Filter(ch, ch1, prime)
ch = ch1
}
}
如何查看频道内部的内容? 例如,我想调试这一行:
prime := <-ch
输入&#39; p ch&#39;在gdb中只打印通道的地址。我怎样才能获得内容?
答案 0 :(得分:1)
你只需要取消引用ch。有一个非常小的程序:
package main
func main() {
ch := make(chan int, 10)
ch <- 1
ch <- 2
ch <- 4
<-ch
}
调试:
(gdb) p *ch
$1 = struct hchan<int> = {1, 2, 4}