我需要运行下面的查询。它问了我很多麻烦。事实上,我有几个" WHERE"条件,需要分解数组的条件。
This issue帮了我,但它没有几个条件" WHERE"
$array = (1,2,3,4,5,6,7,8,9,10);
$clause = implode(',', array_fill(0, count($array), '?'));
if($request = $this->getConnexion()->prepare('SELECT col1, col2 FROM table WHERE col1 IN ('.$clause.') AND col2>=?') or die(mysqli_error($this->getConnexion()))) {
// The problem starts here
call_user_func_array(array($request, 'bind_param'), $array);
$request->bind_param('i', $this->getTime());
// Until here
$request->execute();
$request->bind_result($col1, $col2);
$request->store_result();
// Following the code
}
答案 0 :(得分:2)
重要的是,您只需调用一次bind_param()
,其中包含所有您需要绑定的参数的数组,因此您的解决方案将是只需将额外的WHERE
子句参数添加到要绑定的$array
值即可。 IN()
子句不是需要call_user_func_array()
与其他参数分开的特殊情况。你可以在所有上调用它。
虽然缺少某些东西 - bind_param()
的第一个参数是一串数据类型。您的所有类型都是i
,因此您需要使用str_repeat()
来创建该类型。
// Eventually, this array will contain the other params too
$array = (1,2,3,4,5,6,7,8,9,10);
// This creates a string of ?,?,?,?... for the IN () clause
$clause = implode(',', array_fill(0, count($array), '?'));
// Add the additional value onto the $array array
// so the last param is bound with the others.
$array[] = $this->getTime();
$types = str_repeat('i', count($array));
// The params passed to call_user_func_array() must have as references, each subsequent value. Add those in a loop, but start with the $types string
$params = array($types);
foreach ($array as $key => $value) {
$params[] = &$array[$key];
}
if($request = $this->getConnexion()->prepare('SELECT col1, col2 FROM table WHERE col1 IN ('.$clause.') AND col2>=?') or die(mysqli_error($this->getConnexion()))) {
// Then bind_param() is called on all parameters
// using the $params array which includes types and param references
call_user_func_array(array($request, 'bind_param'), $params);
// Execute & fetch.
$request->execute();
$request->bind_result($col1, $col2);
$request->store_result();
// Following the code
}