我正在尝试开发一个简单的登录系统,但我在数据验证过程中遇到了问题。
如果输入有效数据,一切正常。
但是当我输入无效数据时,它就像空用户或密码,它给我验证erorr,但之后如果我输入正确的用户数据。它不会工作,它只会重新加载相同的页面。 我注意到的奇怪的事情是地址栏上的网址越来越长。
我第一次点击提交按钮后的登录网址。
http://localhost/ci/login/validate
我第二次点击提交按钮后的登录网址。
http://localhost/ci/login/login/validate
每次点击提交按钮,它都会不断向网址添加额外的“/ login”。
知道问题是什么吗?
我的主控制器
<?php if ( ! defined('BASEPATH')) exit('No direct script access allowed');
class Login extends CI_Controller {
public function index()
{
$this->load->view('login/header');
$this->load->view('login/login_view');
$this->load->view('login/footer');
}
public function validate()
{
$this->load->model('login_model');
$this->load->library('form_validation');
$this->form_validation->set_rules('username','Username', 'trim|required|min_length[6]|max_length[50]|valid_email|xss_clean');
$this->form_validation->set_rules('password','Password', 'trim|required|xss_clean');
//validation check
if ($this->form_validation->run() == FALSE)
{
$this->load->view('login/header');
$this->load->view('login/login_view');
$this->load->view('login/footer');
}
else
{
$userdata['username'] = $_POST['username'];
$userdata['password'] = md5($_POST['password']);
//check whether user exist int the database or not
$result = $this->login_model->login_validation($userdata);
//in case user exists
if($result == 1)
{
$this->set_sessions_details();
}
//in case user doesnt exist
else
{
$data['flag'] = "Incorrect Username or Password!";
$this->load->view('login/header');
$this->load->view('login/login_view', $data);
$this->load->view('login/footer');
}
}
}
//load a view in case user exists in the db.
public function set_sessions_details()
{
$this->load->view('test');
}
}
我的模型用于检查数据库中的用户数据。
login_model
class Login_model extends CI_Model
{
function login_validation($userdata)
{
$user=$userdata['username'];
$pass=$userdata['password'];
$result = $this->db->get_where('users', array('username' => $user, 'password' => $pass));
return $result->num_rows();
}
}
?>
我的观点:
login_view
<h3>Please Login</h3>
<form method='post' action='login/validate'>
<div class="form-group" >
<label for="username">Username</label>
<input type="email" class="form-control" name="username" id="username" placeholder="Enter Username">
</div>
<div class="form-group">
<label for="password">Password</label>
<input type="password" class="form-control" name="password" id="password" placeholder="Enter Password">
</div>
<button type="submit" class="btn btn-success">Login</button>
<?php echo validation_errors('<p class"errors">');?>
</form>
<?php if (isset($flag)){ ?>
<p><?php echo $flag; ?> </p>
<?php } ?>
标题
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge">
<meta name="viewport" content="width=device-width, initial-scale=1">
<title>WFD</title>
<link href="<?php echo base_url();?>assets/css/bootstrap.min.css" rel="stylesheet">
<!-- HTML5 shim and Respond.js for IE8 support of HTML5 elements and media queries -->
<!-- WARNING: Respond.js doesn't work if you view the page via file:// -->
<!--[if lt IE 9]>
<script src="https://oss.maxcdn.com/html5shiv/3.7.2/html5shiv.min.js"></script>
<script src="https://oss.maxcdn.com/respond/1.4.2/respond.min.js"></script>
<![endif]-->
</head>
<body>
<div class='container'>
<div class="header">
<center><img src="<?php echo base_url();?>assets/images/logo.png" alt="logo" style="margin-top: 10px; padding-bottom: 20px; opacity: 1;">
<h2>
Welfare Foundation Database
</h2>
</center>
</div>
页脚
</div>
<!-- jQuery (necessary for Bootstrap's JavaScript plugins) -->
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<!-- Include all compiled plugins (below), or include individual files as needed -->
<script src="/ci/assets/js/bootstrap.min.js"></script>
</body>
</html>
答案 0 :(得分:0)
尝试使用表单助手链接中的表单开放标记:https://ellislab.com/codeigniter/user-guide/helpers/form_helper.html
echo form_open('email/send');
在后端将创建
看看这是否解决了您的问题。
答案 1 :(得分:0)
我相信,除了@Abhijit的回答,你的问题就是逻辑本身。你没有重定向到任何地方,你应该是。此外,您不必要地重复调用代码,例如:
$this->load->view('login/header');
$this->load->view('login/login_view');
$this->load->view('login/footer');
只应在一个函数中调用
public function index(){
$this->load->view('login/header');
$this->load->view('login/login_view');
$this->load->view('login/footer');
}
public function validate(){
// your validation logic
if ($this->form_validation->run() == FALSE){
$this->session->set_flashdata('error', array('msg' => 'Upps, something went wrong..', 'anotherParam' => 'anotherText'));
// this will load again the views
redirect('login');
return;
}
}
您现在可以按原样维护表单:
<form method="POST" action="login/validate">
</form>
<?php if($this->session->flashdata('error')){ ?>
<p><?php echo $this->session->flashdata('error')->msg; ?></p>
<?php } ?>
答案 2 :(得分:-1)
在控制器中使用url库:
$this->load->helper('url');
在视图中使用
<form action="<?php echo base_url('login/validate'); ?>" method="POST">
<!-- your input -->
</form>