我正在写一个游戏货币系统的小模型，它或多或少像龙与地下城货币系统或EverquestII货币系统。基本上我有四种不同类型的货币：铜，银，黄金和白金。该系统的汇率为100，所以：
1 Platinum = 100 Gold.
1 Gold = 100 Silver.
1 Silver = 100 Copper.
但问题是，我无法弄清楚如何在彼此之间转换资金，而我的意思是，我无法解决如何将12铂金转换为铜币的问题。高昂的转换率将导致一个非常天文数字。
这是我用来拿钱的课程：
public class CurrencyData
{
public enum CurrencyType
{
Copper ,
Silver ,
Gold ,
Platinum
}
public uint Copper { get; set; }
public uint Silver { get; set; }
public uint Gold { get; set; }
public uint Platinum { get; set; }
public CurrencyData( uint platinum , uint gold , uint silver , uint copper )
{
Copper = copper;
Silver = silver;
Gold = gold;
Platinum = platinum;
}
}
我面临的一个问题是逆向交换。我的意思是假设我想“尝试”将123铜转换为银。那么，这将导致1银币，但是我们有一些无法转换的余数，因为它需要100铜制造1银币。转换后我还会剩余23枚铜币，需要加回到铜币堆中。我怎么做？一般来说，在两个方向转换资金的最佳方式是什么？
编辑：
使用下面的优秀例子，这是我不可避免地最终得到的课程。
using System;
using System.Collections.Generic;
using System.Drawing;
namespace NovaEngine4Framework.Framework.Game.Currency
{
/// <summary>
///
/// CoinBag.cs
/// v1.1.0
/// Gordon Kyle Wallace, "Krythic".
/// LordKrythic@gmail.com
///
/// This class was created with the goal of replicating a "Dungeons and
/// Dragons" or original "Everquest" style currency system. In which there
/// are 4 different levels of currency: Copper, Silver, Gold, and Platinum.
/// Each coin has a different monetary worth, such that Platinum is the most
/// expensive coin, and Copper is the least expensive. The bag holds a desired
/// amount of money, and can be dynamically exchanged with the other denominations
/// at user whim. Each denomination is worth 100 of the lesser, so 1 Platinum is
/// equal to 100 Gold and so on.
///
/// </summary>
public class CoinBag
{
public enum Coins
{
/// <summary>
/// Copper is the lowest denominator of currency.
/// It requires 100 Copper to make 1 Silver.
/// </summary>
Copper = 1 ,
/// <summary>
/// Silver is the second most common form of currency.
/// It requires 100 Silver to Make 1 Gold.
/// </summary>
Silver = 2 ,
/// <summary>
/// Gold is the most common form of currency. It takes
/// part in most expensive transactions.
/// It requires 100 Gold to make 1 Platinum.
/// </summary>
Gold = 3 ,
/// <summary>
/// Platinum is a coin which most people never see. A single
/// Platinum coin can purchase almost anything.
/// 1 Platinum Coin = 100 Gold.
/// 1 Platinum Coin = 10,000 Silver.
/// 1 Platinum Coin = 1,000,000 Copper.
/// </summary>
Platinum = 4
}
private readonly Dictionary<Coins , long> _internalWallet;
public const int CurrencyMinimum = 0;
public const int CurrencyMaximum = 99999;
public const String CopperName = "Copper";
public const String SilverName = "Silver";
public const String GoldName = "Gold";
public const String PlatinumName = "Platinum";
public const char CopperAbbreviation = 'c';
public const char SilverAbbreviation = 's';
public const char GoldAbbreviation = 'g';
public const char PlatinumAbbreviation = 'p';
public static readonly Color CopperTextColor = Color.SaddleBrown;
public static readonly Color SilverTextColor = Color.Silver;
public static readonly Color GoldTextColor = Color.Gold;
public static readonly Color PlatinumTextColor = Color.SlateBlue;
public long Copper { get { return _internalWallet[ Coins.Copper ]; } }
public long Silver { get { return _internalWallet[ Coins.Silver ]; } }
public long Gold { get { return _internalWallet[ Coins.Gold ]; } }
public long Platinum { get { return _internalWallet[ Coins.Platinum ]; } }
public CoinBag( uint platinum , uint gold , uint silver , uint copper )
{
_internalWallet = new Dictionary<Coins , long>
{
{Coins.Platinum, platinum},
{Coins.Gold, gold},
{Coins.Silver, silver},
{Coins.Copper, copper}
};
}
/// <summary>
/// Increases the chosen currency field by a desired amount.
/// </summary>
/// <param name="amount">The amount to be added.</param>
/// <param name="type">The type of currency that will be increased.</param>
public void Add( uint amount , Coins type )
{
_internalWallet[ type ] += amount;
}
/// <summary>
/// Parses the given coin type and returns the in-game
/// text color, which will be used when drawing the name
/// within the game world.
/// </summary>
/// <param name="type"></param>
/// <returns>The color associated with the coin enum to be used for rendering.</returns>
public static Color ParseCoinTextColor( Coins type )
{
switch( type )
{
case Coins.Copper:
return CopperTextColor;
case Coins.Silver:
return SilverTextColor;
case Coins.Gold:
return GoldTextColor;
case Coins.Platinum:
return PlatinumTextColor;
default:
throw new Exception( "Could not parse Coin Color: " + type );
}
}
/// <summary>
/// Retrieves the current balance of a specified coin
/// within the bag, then returns that value with the
/// appended abbreviation attached to the end of it.
/// So, Coins.Copper would return "32c" if the current
/// balance were 32 Copper at the time of invocation.
/// </summary>
/// <param name="coin"></param>
/// <returns>The abbreviated balance of the specified coin.</returns>
public String CheckBalance( Coins coin )
{
switch( coin )
{
case Coins.Copper:
return "" + _internalWallet[ coin ] + CopperAbbreviation;
case Coins.Silver:
return "" + _internalWallet[ coin ] + SilverAbbreviation;
case Coins.Gold:
return "" + _internalWallet[ coin ] + GoldAbbreviation;
case Coins.Platinum:
return "" + _internalWallet[ coin ] + PlatinumAbbreviation;
default:
throw new Exception( "Could not parse Abbreviated Render text: " + coin );
}
}
/// <summary>
/// Parses the given coin type and returns the in-game
/// string abbreviation. Coins.Copper returns 'c'; etc.
/// </summary>
/// <param name="type"></param>
/// <returns>The char abbreviation associated with the coin enum.</returns>
public static char ParseAbbreviation( Coins type )
{
switch( type )
{
case Coins.Copper:
return CopperAbbreviation;
case Coins.Silver:
return SilverAbbreviation;
case Coins.Gold:
return GoldAbbreviation;
case Coins.Platinum:
return PlatinumAbbreviation;
default:
throw new Exception( "Could not parse Coin Abbreviation: " + type );
}
}
/// <summary>
/// Parses the given coin type and returns the in-game
/// string name. Coins.Copper returns "Copper"; etc.
/// </summary>
/// <param name="type"></param>
/// <returns>The String name associated with the coin enum.</returns>
public static String ParseName( Coins type )
{
switch( type )
{
case Coins.Copper:
return CopperName;
case Coins.Silver:
return SilverName;
case Coins.Gold:
return GoldName;
case Coins.Platinum:
return PlatinumName;
default:
throw new Exception( "Could not parse Coin Name: " + type );
}
}
/// <summary>
/// Increases the current balance of this bag with the
/// desired currency.
/// </summary>
/// <param name="platinum">The amount of platinum to be added.</param>
/// <param name="gold">The amount of gold to be added.</param>
/// <param name="silver">The amount of silver to be added.</param>
/// <param name="copper">The amount of copper to be added.</param>
public void Add( uint platinum , uint gold , uint silver , uint copper )
{
_internalWallet[ Coins.Copper ] += copper;
_internalWallet[ Coins.Silver ] += silver;
_internalWallet[ Coins.Gold ] += gold;
_internalWallet[ Coins.Platinum ] += platinum;
}
/// <summary>
/// Increases the current balance of this bag with the
/// current balance of another.
/// </summary>
/// <param name="bag">The other bag.</param>
public void Add( CoinBag bag )
{
_internalWallet[ Coins.Copper ] += bag.Copper;
_internalWallet[ Coins.Silver ] += bag.Silver;
_internalWallet[ Coins.Gold ] += bag.Gold;
_internalWallet[ Coins.Platinum ] += bag.Platinum;
}
/// <summary>
/// Subtracts the chosen currency by a desired amount.
/// </summary>
/// <param name="amount">The amount to subtract.</param>
/// <param name="type">The type of money that will be subtracted.</param>
public void Subtract( uint amount , Coins type )
{
_internalWallet[ type ] -= amount;
}
/// <summary>
/// Subtracts the current balance of the Coinbag with
/// the desired fields.
/// </summary>
/// <param name="platinum">The amount of Platinum to subtract.</param>
/// <param name="gold">The amount of Gold to subtract.</param>
/// <param name="silver">The amount of silver to subtract.</param>
/// <param name="copper">The amount of copper to subtract.</param>
public void Subtract( uint platinum , uint gold , uint silver , uint copper )
{
_internalWallet[ Coins.Copper ] -= copper;
_internalWallet[ Coins.Silver ] -= silver;
_internalWallet[ Coins.Gold ] -= gold;
_internalWallet[ Coins.Platinum ] -= platinum;
}
/// <summary>
/// Subtracts the current balance of the Coinbag with
/// the balance of another.
/// </summary>
/// <param name="bag">The second bag.</param>
public void Subtract( CoinBag bag )
{
_internalWallet[ Coins.Copper ] -= bag.Copper;
_internalWallet[ Coins.Silver ] -= bag.Silver;
_internalWallet[ Coins.Gold ] -= bag.Gold;
_internalWallet[ Coins.Platinum ] -= bag.Platinum;
}
/// <summary>
/// Completley Balances the current CoinBag by shifting
/// over Copper->Silver->Gold->Platinum.
/// </summary>
public void Balance()
{
Exchange( Coins.Copper , Coins.Silver , Copper );
Exchange( Coins.Silver , Coins.Gold , Silver );
Exchange( Coins.Gold , Coins.Platinum , Gold );
}
/// <summary>
/// Completely Empties the wallet of all money.
/// </summary>
public void Empty()
{
_internalWallet[ Coins.Copper ] -= 0;
_internalWallet[ Coins.Silver ] -= 0;
_internalWallet[ Coins.Gold ] -= 0;
_internalWallet[ Coins.Platinum ] -= 0;
}
/// <summary>
/// Exchanges one field of currency to another based
/// upon its monetary worth. The exchange rate for
/// all currency is 100 of the lesser.
/// 100 Gold = 1 Platinum.
/// 100 Silver = 1 Gold.
/// 100 Copper = 1 Silver.
/// </summary>
/// <param name="fromType">The Type that will be exchanged.</param>
/// <param name="toType">What the fromType will be exchanged to.</param>
/// <param name="amountOfFromType">The amount to be exchanged.</param>
public void Exchange( Coins fromType , Coins toType , long amountOfFromType )
{
if( fromType == toType )
return;
long fromTypeAmount = _internalWallet[ fromType ];
if( amountOfFromType > fromTypeAmount )
return; // Not enough money.
if( fromType > toType )
{
_internalWallet[ toType ] += amountOfFromType * ( long )Math.Pow( 100 , ( int )fromType - ( int )toType );
}
else
{
long overflow = amountOfFromType % 100;
amountOfFromType -= overflow;
_internalWallet[ toType ] += amountOfFromType / ( long )Math.Pow( 100 , ( int )toType - ( int )fromType );
}
_internalWallet[ fromType ] -= amountOfFromType;
}
/// <summary>
/// Creates a String representation for the current
/// monetary state of the coinbag. The format is
/// as follows:
/// [ Platinum->Gold->Silver->Copper ]
/// Or:
/// [ 100p,23g,17s,780c ]
/// </summary>
/// <returns>A String reprsentation of the Coinbag.</returns>
public String ToCurrencyString()
{
return
"" + Platinum + PlatinumAbbreviation + "," +
Gold + GoldAbbreviation + "," +
Silver + SilverAbbreviation + "," +
Copper + CopperAbbreviation;
}
}
}
答案 0 :(得分：3)
这是我怎么做的。首先，将值分配给CurrencyType以了解具有更高价值的值并将其用于转换。
public enum CurrencyType
{
Copper = 1,
Silver = 2,
Gold = 3,
Platinum = 4
}
然后让CurrencyData类看下面的内容。如果你担心天文数字，我会用很久。
private readonly Dictionary<CurrencyType, long> data;
public long Platinum { get { return data[CurrencyType.Platinum]; } }
... properties for other currencies
public CurrencyData(long platinum, long gold, long silver, long copper)
{
data = new Dictionary<CurrencyType, long>
{
{ CurrencyType.Platinum, platinum },
{ CurrencyType.Gold, gold },
{ CurrencyType.Silver, silver },
{ CurrencyType.Copper, copper }
};
}
最后，转换方法
public void Exchange(CurrencyType fromType, CurrencyType toType, long amountOfFromType)
{
if (fromType == toType)
return;
var fromTypeAmount = data[fromType];
if (amountOfFromType > fromTypeAmount)
throw new InvalidOperationException("Not enough money");
if (fromType > toType)
{
data[toType] += amountOfFromType * (long) Math.Pow(100, (int)fromType - (int)toType);
}
else
{
var overflow = amountOfFromType % 100;
amountOfFromType -= overflow;
data[toType] += amountOfFromType / (long) Math.Pow(100, (int)toType - (int)fromType);
}
data[fromType] -= amountOfFromType;
}
您可以尝试
wallet.Exchange(CurrencyType.Platinum, CurrencyType.Gold, 3);
wallet.Exchange(CurrencyType.Copper, CurrencyType.Silver, 125);
答案 1 :(得分：1)
答案很简单。使用CurrencyData对象保存结果。其余的都是数学的。而且由于你使用的是100个单位，所以它更简单，因为你使用的是基于常规的编号......
转换
简单地从上到下移动，然后乘以100 ...不知道为什么你会这样做但是就这么简单！
<强> 实施例
//gold to silver
this.SilverCount += this.GoldCount * 100;
this.GoldCount = 0;
//silver to copper
this.CopperCount += this.SilverCount * 100;
this.SilverCount = 0;
转换
只需从下往上移动，除以100，然后保留其余部分......
<强> 实施例
//copper to silver
this.SilverCount += (this.CopperCount / 100);
this.CopperCount = this.CopperCount % 100;
//silver to gold
this.GoldCount += (this.SilverCount / 100);
this.SilverCount = this.SilverCount % 100;
希望这会有所帮助......