Question

错误：

注意：尝试在第16行的C：\ Users \ Gustavs \ Documents \ EasyPHP \ test2 \ register.php中获取非对象的属性
注意：尝试在第20行的C：\ Users \ Gustavs \ Documents \ EasyPHP \ test2 \ register.php中获取非对象的属性代码：

$exists = '';
$result = $connect->query('SELECT username FROM users WHERE username = '.$username.' LIMIT 1');
if ($result->num_rows == 1) {
    $exists = 'u';
}   
$result = $connect->query('SELECT email from users WHERE email = '.$email.' LIMIT 1');
if ($result->num_rows == 1) {
    $exists = 'e';
}

16行：

if ($result->num_rows == 1) {

20行：

if ($result->num_rows == 1) {

Answer 1

试试这个：

    $exists = '';
    if($result = $connect->query('SELECT username FROM users WHERE username = "'.$username.'" LIMIT 1')){
        if($result->num_rows == 1){
        $exists = 'u';
        }else{
            die;
        }
    }   
    if($result = $connect->query('SELECT email FROM users WHERE email = "'.$email.'" LIMIT 1')){
        if($result->num_rows == 1){
        $exists = 'e';
        }else{
           die;
        }
    }

或者，根据您如何检查查询是否成功，您可以执行以下操作：

    $exists = '';
    if($result = $connect->query('SELECT username FROM users WHERE username = "'.$username.'" LIMIT 1')){
        if($result->num_rows == 1){
        $exists = 'u';
        }
        return true;
    }else{
        return false;
    }   
    if($result = $connect->query('SELECT email FROM users WHERE email = "'.$email.'" LIMIT 1')){
        if($result->num_rows == 1){
        $exists = 'e';
        }
        return true;
    }else{
        return false;
    }

甚至：

    $exists = '';
    if($result = $connect->query('SELECT username FROM users WHERE username = "'.$username.'" LIMIT 1')){
        if($result->num_rows == 1){
        $exists = 'u';
        }
        echo 'Success!';
    }else{
        echo 'Failure!';
    }   
    if($result = $connect->query('SELECT email FROM users WHERE email = "'.$email.'" LIMIT 1')){
        if($result->num_rows == 1){
        $exists = 'e';
        }
        echo 'Success!';
   }else{
        echo'Failure';
    }

我希望这有帮助！

尝试使用if函数获取非对象的属性

1 个答案: