SQL行比较查询

时间:2015-01-17 19:19:34

标签: mysql sql qsqlquery

我是SQL新手并试图针对以下结果表编写查询,这样我就可以列出学生Mary得分高于Tom的科目。

    Subject        Student        Teacher        Score
    --------------------------------------------------
    Maths           Tom            Anderson        67
    Maths           Mary           Anderson        68
    English         Tom            Lewis           55
    English         Mary           Lewis           44
    French          Tom            Joubert         87
    French          Mary           Joubert         76
    Geography       Tom            Arnold          76
    Geography       Mary           Arnold          82

结果应该是一个表格如下:

    Subject     
    ---------
    Maths
    Geography

我相信我应该使用join子句但是无法使用它。

由于

3 个答案:

答案 0 :(得分:2)

假设没有重复的分数,您实际上可以通过聚合执行此操作。

select subject
from results
group by subject
having max(case when student = 'Mary' then score end) >
       max(case when student = 'Tom' then score else 0 end);

请注意,这将包括Mary有分数但Tom没有的主题。

答案 1 :(得分:0)

您可以使用自连接对此进行概括,如下所示:

SQL Fiddle

查询:

select a.Student As higher, b.Student as lower, a.Subject
  from score a
  join score b   ON a.Student <> b.Student
                AND a.Subject = b.Subject
                AND a.Score > b.Score

<强> Results

| HIGHER | LOWER |   SUBJECT |
|--------|-------|-----------|
|   Mary |   Tom |     Maths |
|    Tom |  Mary |   English |
|    Tom |  Mary |    French |
|   Mary |   Tom | Geography |

然后,显然,您可以通过添加此WHERE子句来过滤结果。

where a.student ='Mary' AND b.student = 'Tom

答案 2 :(得分:0)

此查询将为您提供所需的结果:

SELECT subject
FROM   scores
WHERE  student = 'Mary'
AND    ( subject
       , score
       ) IN (
            SELECT   subject
            ,        MAX( score )
            FROM     scores
            GROUP BY subject
            );