这是我在DynamicViewsTable.php
中的自定义finder方法public function findAccessibleByUser(Query $query, array $options)
{
if (empty($options['User']['id'])) {
throw new Exception("Current User not set", 1);
}
$query->select(['DynamicViews.id', 'DynamicViews.title', 'UsersAccessDynamicViews.ordinal_ranking'])
->contain(['UsersAccessDynamicViews'])
->where([
'UsersAccessDynamicViews.user_id' => $options['User']['id'],
])
->order(['UsersAccessDynamicViews.ordinal_ranking' => 'ASC']);
return $query;
}
我不断得到的错误是:
Error: SQLSTATE[42S22]: Column not found: 1054 Unknown column 'UsersAccessDynamicViews.ordinal_ranking' in 'field list'
并且错误页面中显示的查询是:
SELECT DynamicViews.id AS `DynamicViews__id`, DynamicViews.title AS `DynamicViews__title`, UsersAccessDynamicViews.ordinal_ranking AS `UsersAccessDynamicViews__ordinal_ranking` FROM dynamic_views DynamicViews WHERE UsersAccessDynamicViews.user_id = :c0 ORDER BY UsersAccessDynamicViews.ordinal_ranking ASC
DynamicViews拥有多个UsersAccessDynamicViews
答案 0 :(得分:5)
虽然您可以使用contain()
添加任何类型的关联,但匹配某些内容仅适用于1:1
和n:1
关联,即hasOne
和belongsTo
,因为这些是contain()
将加入相关表格的唯一关联。
出于所有其他目的,您必须使用 matching()
(需要最近的开发快照才能与contain()
结合使用,特别是for more complex combinations )
$query
->select(['DynamicViews.id', 'DynamicViews.title', 'UsersAccessDynamicViews.ordinal_ranking'])
->contain(['UsersAccessDynamicViews'])
->matching('UsersAccessDynamicViews', function ($q) use ($options) {
return $q->where([
'UsersAccessDynamicViews.user_id' => $options['User']['id']
]);
})
->order(['UsersAccessDynamicViews.ordinal_ranking' => 'ASC']);
手动join in 相关表格:
$query
->select(['DynamicViews.id', 'DynamicViews.title', 'UsersAccessDynamicViews.ordinal_ranking'])
->contain(['UsersAccessDynamicViews'])
->innerJoin('UsersAccessDynamicViews', [
'UsersAccessDynamicViews.dynamic_view_id = DynamicViews.id',
'UsersAccessDynamicViews.user_id' => $options['User']['id']
])
->order(['UsersAccessDynamicViews.ordinal_ranking' => 'ASC']);
或从另一张表中查询。
另见