无法在div php中正确生成结果

时间:2015-01-17 12:57:08

标签: php mysql

我不太确定如何将它们用语言表达。我试图在每个div中显示结果,如图中所示,但不幸的是,我只能使它只出现在"引用请求中#34; DIV。 我可以知道我哪里出错了吗?

<?php
            $query2 = "SELECT * FROM client c, sales_card s WHERE c.id = s.client_id and emp_id_followup = '".$_SESSION["ID"]."'";
            $result2 = mysql_query($query2);
            if (mysql_num_rows($result2) > 0) {
                while($row2 = mysql_fetch_assoc($result2)) {
                    $swimlaneID = $row2['swimlane_id'];
                }
            }

            $query = "SELECT * FROM swimlane";
            $result = mysql_query($query);
            if (mysql_num_rows($result) > 0) {
                while($row = mysql_fetch_assoc($result)) {
                    echo '<div id="right">'; 
                    echo '<div style="border-style:solid; height:1020px;">';
                    echo '<h2>'. $row["swimlane_name"].'</h2>';
                    echo '<ul id="'. $row["shortform"].'">';
                    if ($swimlaneID == $row["id"])
                    {
                     echo $display-> $row["shortform"]();
                    }
                    echo '</ul>';
                    echo '</div>';
                    echo '</div>';
                }
            }else{
            echo "no row";
            }
        ?>

this is what I would like to achieve

0 个答案:

没有答案