Question

我有2个表一个是buy_table，另一个是sale_table。在此查询中的此查询中，我将不得不使用SUM，分组依据和日期，但我无法理解并显示som错误

//buy table
----------------------------------------------------------
| id | product_id | quantity | total_price | date       |
----------------------------------------------------------
| 1  | 1          | 5        |   500       | 2014-12-05 |
----------------------------------------------------------
| 2  | 2          | 5        |   500       | 2014-12-15 |
----------------------------------------------------------
| 3  | 1          | 5        |   500       | 2014-12-01 |

//Sale_table
----------------------------------------------------------
| id | product_id | quantity | total_price | date       |
----------------------------------------------------------
| 1  | 1          | 5        |   1800      | 2014-12-05 |
----------------------------------------------------------
| 2  | 2          | 5        |   500       | 2014-12-15 |
----------------------------------------------------------
| 3  | 3          | 5        |   500       | 2015-01-01 |
----------------------------------------------------------
| 4  | 3          | 5        |   500       | 2015-01-01 |

我需要这样。

----------------------------------------------------------------------
| id | product_id |buy_quantity| buy_total | sale_quantity|sale_total 
----------------------------------------------------------------------
| 1  | 1          | 10       |   1000      |    5         |  1800
----------------------------------------------------------------------
| 2  | 2          | 5        |   500       |    5         |  500
----------------------------------------------------------------------
| 3  | 3          | 5        |   500       |    10        |  1000
----------------------------------------------------------------------

Answer 1

如果您想按产品展示买/卖，结果中的ID列没有意义。

为了确保您始终获得所有产品，您需要使用产品表作为驱动表（假设您有产品表）

select
p.product_id,
(SELECT SUM(b.quantity) FROM buy b WHERE b.product_id = p.product_id) as buy_quantity, 
(SELECT SUM(b.total_price) FROM buy b WHERE b.product_id = p.product_id) as buy_total,
(SELECT SUM(s.quantity) FROM sale s WHERE s.product_id = p.product_id) as sale_quantity, 
(SELECT SUM(s.total_price) FROM sale s WHERE s.product_id = p.product_id) as sale_total 
from product p

Answer 2

    SELECT 
A.ID,A.PRODUCT_ID,A.BUY_QUANTITY,B.SALE_QUANTITY,A.BUY_TOTAL,B.SALE_TOTAL,A.DATE
(select id,product_id,sum(quantity) as buy_quantity,sum(total_price) as 
buy_total,date  from buy_table group by product_id) A INNER JOIN (SELECT sum
(quantity) as SALE_quantity,sum(total_price) as SALE_total FROM SALE_TABLE  group by product_id) B 
ON A.PRODUCT_ID=B.PRODUCT_ID

Answer 3

我认为您错误输入了买表中的第三行，并且您打算在product_id中输入3并且所需结果集中的id列只是一个与任何无关的序列数据。以下查询可能是您查询的答案：

-- Simluating your tables
DECLARE @buyTable AS TABLE (id INT, product_id INT, quantity INT, total_price INT, date DATE)
DECLARE @saleTable AS TABLE (id INT, product_id INT, quantity INT, total_price INT, date DATE)
INSERT INTO @buyTable
VALUES(1, 1, 5, 500, '2014-12-05'), (2, 2, 5, 500, '2014-12-15'), (3, 3, 5, 500, '2014-12-01')
INSERT INTO @saleTable
VALUES(1, 1, 5, 1800, '2014-12-05'), (2, 2, 5, 500, '2014-12-15'), (3, 3, 5, 500, '2014-01-01'), (4, 3, 5, 500, '2015-01-01')
-- Simluation stops here

SELECT ROW_NUMBER() OVER(ORDER BY b.product_id) AS id, b.product_id, buy_quantity, buy_total, sale_quantity, sale_total FROM
(
    SELECT product_id, SUM(quantity) AS buy_quantity, SUM(total_price) AS buy_total FROM @buyTable
    GROUP BY product_id
) b
INNER JOIN
(
    SELECT product_id, SUM(quantity) AS sale_quantity, SUM(total_price) AS sale_total FROM @saleTable
    GROUP BY product_id
) s ON s.product_id = b.product_id

使用SUM和Group By连接2表

3 个答案: