我有这个查询wrtiien PL / SQL
if l_rec.sched_interval_type = 'DAYS' then
if l_max_date is null then
if l_rec.DAY_START_DAY is not null then
SELECT next_day(p_date, l_rec.DAY_START_DAY)
INTO l_start_date
FROM dual;
else
l_start_date := TRUNC(p_date);
end if;
我尝试将其翻译为SQL SERVER
set @NextDayID =(SELECT DAY_START_DAY FROM #l_rec )
SELECT CASE WHEN sched_interval_type = 'DAYS' then
CASE WHEN @l_max_date is null then
CASE WHEN @NextDayID is not null then
@l_start_date = DATEADD(DAY, (DATEDIFF(DAY, ((@NextDayID + 5) % 7), GETDATE()) / 7) * 7 + 7, ((@NextDayID + 5) % 7))
else
@l_start_date =CONVERT(DATETIME, CONVERT(DATE, @p_date))
end
我遇到很多错误,如何纠正错误?
答案 0 :(得分:0)
试试这个:
DECLARE @NextDayID INT
SELECT @NextDayID = DAY_START_DAY FROM #l_rec
SELECT @l_start_date CASE WHEN sched_interval_type = 'DAYS' and @l_max_date is null and @NextDayID is not null then
DATEADD(DAY, (DATEDIFF(DAY, ((@NextDayID + 5) % 7), GETDATE()) / 7) * 7 + 7, ((@NextDayID + 5) % 7))
else CONVERT(DATETIME, CONVERT(DATE, @p_date)) end as [start_date]
from <<someTableName>> --<<--Replace the tag with the table whihc has the column `sched_interval_type`