Question

我开始在Xamarin开发，然后决定许可证可能有点贵，所以我将我的代码转移到java。

我有一个使用JSON对象执行POST的小块，它在Xamarin中工作，doest在Java中工作。

Xamarin：

    var client = new HttpClient ();
    var content = new FormUrlEncodedContent(new Dictionary<string, string>() { 
        {"action", "getEpisodeJSON"},
        {"episode", "11813"}

    });
    client.DefaultRequestHeaders.Referrer = new Uri(link);

    var resp = client.PostAsync("http://www.ts.kg/ajax", content).Result;
    var repsStr = resp.Content.ReadAsStringAsync().Result;
    dynamic res = JsonConvert.DeserializeObject (repsStr);

机器人：

    HttpClient httpclient = new DefaultHttpClient();

    // 2. make POST request to the given URL
    HttpPost httpPost = new HttpPost("http://www.ts.kg/ajax");

    String json = "";

    // 3. build jsonObject
    JSONObject jsonObject = new JSONObject();
    jsonObject.accumulate("action", "getEpisodeJSON");
    jsonObject.accumulate("episode", "11813");

    // 4. convert JSONObject to JSON to String
    json = jsonObject.toString();

    // 5. set json to StringEntity
    StringEntity se = new StringEntity(json);

    // 6. set httpPost Entity
    httpPost.setEntity(se);

    // 7. Set some headers to inform server about the type of the content
    httpPost.setHeader("Accept", "application/json");
    httpPost.setHeader("Content-type", "application/json");
    httpPost.addHeader("Referer", "http://www.ts.kg");

    // 8. Execute POST request to the given URL
    HttpResponse httpResponse = httpclient.execute(httpPost);

    // 9. receive response as inputStream
    InputStream inputStream = httpResponse.getEntity().getContent();

    // 10. convert inputstream to string
    String result;
    if(inputStream != null)
        result = convertInputStreamToString(inputStream);

在Android中进行此类POST的正确方法是什么？

UPD 目前的问题是我得到一个空的结果字符串;

    private static String convertInputStreamToString(InputStream inputStream) throws IOException{
        BufferedReader bufferedReader = new BufferedReader( new InputStreamReader(inputStream));
        String line = "";
        String result = "";
        while((line = bufferedReader.readLine()) != null)
            result += line;

        inputStream.close();
        return result;

    }

Answer 1

我最终通过Fiddle捕获了我的设备的所有请求（好的教程在这里：http://tech.vg.no/2014/06/04/how-to-monitor-http-traffic-from-your-android-phone-through-fiddler/）

区别在于cookie，所以我使用了HttpContex变量，如下所述： Android HttpClient Cookie

我也有不同的Content-Type，所以我手动设置这个标题：

httpPost.setHeader("Content-Type", "application/x-www-form-urlencoded");

代码适用于Xamarin Android但不适用于Java（HttpPost JSON）

1 个答案: