RTI.hh中的错误，预期的构造函数，析构函数或类型转换之前＆＃39;＆amp;＆＃39;代币

Question

我有一个建模环境，我正在尝试使用CERTI高级语言架构运行时基础结构进行编译。在[编译过程中，我遇到了几行代码，我不明白，这也会让编译器失误。

RTI_STD::ostream RTI_EXPORT &
operator<<(RTI_STD::ostream &, RTI::Exception *ex)

返回的错误在标题上方。任何帮助将不胜感激。

---

编辑1

更多信息：

这是我相信的相关代码：

class RTI_EXPORT RTI
{
public:
#include "baseTypes.hh"
#include "RTItypes.hh"

/**
 * RTI (RunTime Infrastructure) Ambassador class.
 * The RTIambassador class is the interface used by an
 * HLA federate to call the RTI. The RTI may call the
 * federate back using the Federate Ambassador class
 * @see FederateAmbassador.
 */
class RTI_EXPORT RTIambassador
{
public:
#include "RTIambServices.hh"
RTIambPrivateData *privateData ;
private:
RTIambPrivateRefs* privateRefs ;
};

/**
 * Federate Ambassador class.
 * The FederateAmbassador is the structure RTI callback class.
 * When the RTI needs to contact the federate it calls one
 * of the FederateAmbassador class methods.
 */
class RTI_EXPORT FederateAmbassador
{
public:
#include "federateAmbServices.hh"
};
};

RTI_STD::ostream RTI_EXPORT &
operator<<(RTI_STD::ostream &os, RTI::Exception *ex);

RTI_STD::ostream RTI_EXPORT &
operator<<(RTI_STD::ostream &os, RTI::Exception const &ex);

如果您想要整个文件，我可以提供链接。

我认为我的主要问题是我不确定这里使用的＆符号是什么？有什么提示吗？