我希望在一个表中插入数据,并通过 mysqli 中的预准备语句在另一个表中更新数据。尝试以下操作仅执行INSERT命令:
编辑:
if($stmt=$mysqli->prepare("SELECT bids_id, bid, fruit_volume FROM basket ORDER BY bid DESC")) {
$stmt->execute();
$stmt->store_result();
$stmt->bind_result($bids_id, $bid, $fruit_volume);
while($stmt->fetch()) {
$stack = array($bids_id, $bid, $fruit_volume);
array_push($all_fruits, $stack);
}
$stmt->free_result();
}
foreach ($all_fruits as $fruits) {
if ($_POST["offer"] == $fruits[1] && $volume < $fruits[2]) {
$stmt2 = $mysqli->prepare("INSERT INTO oranges (username, price, volume, date) VALUES (?, ?, ?, ?)");
$stmt2->bind_param('sdis', $user, $price, $volume, $today);
$stmt2->execute();
$stmt3 = $mysqli->prepare("UPDATE basket SET fruit_volume = ? WHERE bids_id = ?");
$stmt3->bind_param('ii', 800, 1);
$stmt3->execute();
}
}
$mysqli->close();
答案 0 :(得分:2)
试试这个
foreach ($all_fruits as $fruits) {
if ($_POST["offer"] == $fruits[1] && $volume < $fruits[2]) {
$stmt2 = $mysqli->prepare("INSERT INTO oranges (username, price, volume, date) VALUES (?, ?, ?, ?)");
$stmt2->bind_param('sdis', $user, $price, $volume, $today);
$stmt2->execute();
$stmt3 = $mysqli->prepare("UPDATE basket SET fruit_volume = ? WHERE bids_id = ?");
$stmt3->bind_param('ii', 800, 1);
$stmt3->execute();
}
}
$mysqli->close();
答案 1 :(得分:2)
bind_param通过引用传递而不是按值传递,因此您需要在引用它们之前将这些值包含在变量中
$a=800;
$b=1;
foreach ($all_fruits as $fruits) {
if ($_POST["offer"] == $fruits[1] && $volume < $fruits[2]) {
$stmt2 = $mysqli->prepare("INSERT INTO oranges (username, price, volume, date) VALUES (?, ?, ?, ?)");
$stmt2->bind_param('sdis', $user, $price, $volume, $today);
$stmt2->execute();
$stmt3 = $mysqli->prepare("UPDATE basket SET fruit_volume = ? WHERE bids_id = ?");
$stmt3->bind_param('ii',$a, $b);
$stmt3->execute();
}
}