是否可以从变量设置*args
?
def fn(x, *args):
# ...
# pass arguments not as list but each as single argument
arguments = ??? # i.e.: ['a', 'b']
fn(1, arguments)
# should be equivalent to
fn(1, 'a', 'b')
答案 0 :(得分:5)
是的,你可以使用参数解包(也称为splatting):
fn(1, *arguments)
以下是演示:
>>> def fn(x, *args):
... return args
...
>>> arguments = ['a', 'b']
>>> fn(1, *arguments)
('a', 'b')
>>>
答案 1 :(得分:0)
# pass arguments not as list but each as single argument
arguments = ??? # i.e.: ['a', 'b']
然后应该为arguments = ['a' ,'b']
分配参数。这是参数解包。