Question

我有一个字符串

Mystring = "123 456 789, 234, 999|567 888[222"

我想将此字符串拆分为" " "," "|"和"["以获取列表中的所有数字

预期产出： -

List = ["123","456","789","234","999",567","888","222"]

我正在使用以下代码

Final_List = re.findall("(\d+?)[ ,|\]]",Mystring)

实际输出：

["123","456","789",234","999",567"]

我如何在这里获得所有数字？

Answer 1

为什么不直接获取数字，而不是分割字符串：

>>> import re
>>> Mystring = "123 456 789, 234, 999|567 888[222"
>>> re.findall('\d+', Mystring)
['123', '456', '789', '234', '999', '567', '888', '222']
>>>

\d+ Python匹配一个或多个数字（数字）。

Answer 2

import string
tbl = string.maketrans(',|[',"   ")

print(Mystring.translate(tbl)).split()
['123', '456', '789', '234', '999', '567', '888', '222']


In [29]: import string

In [30]: %%timeit
   ....: tbl = string.maketrans(',|[',"   ")
   ....: (Mystring.translate(tbl)).split()
   ....: 
1000000 loops, best of 3: 762 ns per loop

In [31]: import re

In [32]: timeit re.findall('\d+', Mystring)
100000 loops, best of 3: 2.99 µs per loop

拆分一个字符串（在空格或标点符号上）以获取所有数字

2 个答案: