Question

我有3列

Order_ID上
Activation_Date
Order_Received_Date

因此，如果我明确计算Order_Received_Date上的所有order_ID，我将获得“订单数量”同样，如果我明确计算Activation_Date上的所有order_ID，我将获得“激活次数”

我想要的是两列名为“#Orders”和“#Activations”

感谢任何输入，谢谢

Answer 1

我使用union all进行此类计算。以下是标准SQL，因此它应该适用于任何数据库：

select thedate, sum(r) as numorders, sum(a) as numactivations
from (select activation_date as thedate, 1 as a, 0 as r from table t
      union all
      select order_received_date, 0, 1 from table t
     ) t
group by thedate
order by thedate;

Answer 2

如果我理解正确，我猜以下查询可能会帮助您解决此问题：

SELECT 
    OrderID,
    ActivationDate,
    OrderReceivedDate,
    COUNT(OrderID) OVER (),
    COUNT(ActivationDate) OVER ()
FROM
(
    SELECT 1 AS OrderID, '2014-01-01' AS ActivationDate, '2013-12-15' AS OrderReceivedDate UNION
    SELECT 2 AS OrderID, NULL AS ActivationDate, '2013-12-19' AS OrderReceivedDate UNION
    SELECT 3 AS OrderID, '2014-03-01' AS ActivationDate, '2013-12-17' AS OrderReceivedDate UNION
    SELECT 4 AS OrderID, '2014-04-01' AS ActivationDate, '2013-12-03' AS OrderReceivedDate
) t

我希望这可以帮助你...

多个日期与计数

2 个答案: