逗号分隔列表到字符串sql

Question

我需要从变量中转换以下值：

1234,1234,12345,12346,1344,4564

到此：

'1234','1234','12345','12346','1344','4564'

使用SQL函数。

我试过了：

DECLARE @VAL AS VARCHAR(MAX)
SELECT @VAL = '1234,1234,12345,12346,1344,4564'

DECLARE @listStr VARCHAR(MAX)
SELECT @listStr = COALESCE(@listStr+',' ,'') + @VAL
SELECT @listStr AS 'List'
GO

但我明白了：

1234,1234,12345,12346,1344,4564

Answer 1

试试这个：

SELECT '''' + REPLACE('1234,1234,12345,12346,1344,4564', ',', ''',''') + '''';

选中 SQL FIDDLE DEMO

<强>输出

|                                    COLUMN_0 |
|---------------------------------------------|
| '1234','1234','12345','12346','1344','4564' |

修改

使用用户定义的功能：

CREATE FUNCTION dbo.ufnReplace(@Val VARCHAR(MAX))
RETURNS VARCHAR(MAX) 
AS 
BEGIN
    SELECT @Val = '''' + REPLACE(@Val, ',', ''',''') + '''';
    RETURN @Val;
END;

SELECT dbo.ufnReplace('1234,1234,12345,12346,1344,4564');

Answer 2

DECLARE @VAL AS VARCHAR(MAX)
SELECT @VAL = '1234,1234,12345,12346,1344,4564'
SELECT '''' + REPLACE(@VAL,',',''',''') + ''''

Answer 3

使用REPLACE()和CONCAT()：

select concat("\'", replace('1234,1234,12345,12346,1344,4564', ',', "\',\'"), "\'")